A marble statue has a mass of 6,200 grams and a volume of 2,296 cm3. What is the density of marble?

How do you know if a boy like you?

adell [148]

Answer:

They cherish you

Explanation:

6 0

3 years ago

A watermelon is dropped from the top of a 80m tall building. We want to find the velocity of the watermelon after it falls for 1

White raven [17]

Answer:

$v_f = v_i + at$

$v_f = 13.23 m/s$

Explanation:

Height Of the watermelon when it is dropped is given as

$h = 80 m$

time of fall under gravity

$t = 1.35 s$

now if water melon start from rest then we have

$v_i = 0$

acceleration due to gravity for watermelon

$a = 9.81 m/s^2$

now we need to find the final speed of watermelon

$v_f = v_i + at$

so we will have

$v_f = 0 + (9.81)(1.35)$

$v_f = 13.23 m/s$

7 0

4 years ago

A proton has been accelerated from rest through a potential difference of -1000 v . part a what is the proton's kinetic energy,

wlad13 [49]

We can apply the law of conservation of energy here. The total energy of the proton must remain constant, so the sum of the variation of electric potential energy and of kinetic energy of the proton must be zero:
$\Delta U + \Delta K=0$
which means
$\Delta K = - \Delta U$
The variation of electric potential energy is equal to the product between the charge of the proton (q=1eV) and the potential difference ( $\Delta V=-1000 V$ ):
$\Delta U = q \Delta V=(1 eV)(-1000 V)=-1000 eV$
Therefore, the kinetic energy gained by the proton is
$\Delta K = -(-1000 eV)=1000 eV$
<span>And since the initial kinetic energy of the proton was zero (it started from rest), then this 1000 eV corresponds to the final kinetic energy of the proton.</span>

4 0

3 years ago

Read 2 more answers

Determine the change in electric potential energy of a system of two charged objects when a -2.1-C charged object and a -5.0-C c

elena55 [62]

Answer:

Change in electric potential energy ∆E = 365.72 kJ

Explanation:

Electric potential energy can be defined mathematically as:

E = kq1q2/r ....1

k = coulomb's constant = 9.0×10^9 N m^2/C^2

q1 = charge 1 = -2.1C

q2 = charge 2 = -5.0C

∆r = change in distance between the charges

r1 = 420km = 420000m

r2 = 160km = 160000m

From equation 1

∆E = kq1q2 (1/r2 -1/r1) ......2

Substituting the given values

∆E = 9.0×10^9 × -2.1 ×-5.0(1/160000 - 1/420000)

∆E = 94.5 × 10^9 (3.87 × 10^-6) J

∆E = 365.72 × 10^3 J

∆E = 365.72 kJ

6 0

3 years ago

How do you calculate the mass of an object accelerating at22.35m/s2 with a force of 120N

Arte-miy333 [17]

Answer:

The mass of object is calculated as 5.36 kg

Explanation:

The known terms to find the mass are:

acceleration of object (a) = 22.35 $m/s^{2}$

Force exerted (F) = 120N

mass of an object (m) = ?

From Newton's second law of motion;

F = ma

or, 120 = m × 22.35

or, m= $\frac{120}{22.35}$ kg

∴ m = 5.36 kg

3 0

3 years ago