All categories

3 years ago

Which statement correctly compares the fraction?

Mathematics

2 answers:

raketka [301]3 years ago

4 0

B. Ecause if you had a pie, and you cut it into 5ths and another pie into 4 ths, and ate 3 slices of each you would have more of 3/4.
Hope this is fine

jek_recluse [69]3 years ago

3 0

The answer is B, 3/4 is greater than 3/5

3/4=0.75
3/5=0.6

0.75 is greater than 0.6

You might be interested in

A test consists of 10 true/false questions. To pass the test a student must answer at least 6 questions correctly. If a student

Mademuasel [1]

Answer:

37.70% probability that the student will pass the test

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the student guesses it correctly, or he does not. The probability of a student guessing a question correctly is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

10 true/false questions.

10 questions, so $n = 10$

True/false questions, 2 options, one of which is correct. So $p = \frac{1}{2} = 0.5$

If a student guesses on each question, what is the probability that the student will pass the test?

$P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{10,6}.(0.5)^{6}.(0.5)^{4} = 0.2051$

$P(X = 7) = C_{10,7}.(0.5)^{7}.(0.5)^{3} = 0.1172$

$P(X = 8) = C_{10,8}.(0.5)^{8}.(0.5)^{2} = 0.0439$

$P(X = 9) = C_{10,9}.(0.5)^{9}.(0.5)^{1} = 0.0098$

$P(X = 10) = C_{10,10}.(0.5)^{10}.(0.5)^{0} = 0.0010$

$P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.2051 + 0.1172 + 0.0439 + 0.0098 + 0.0010 = 0.3770$

37.70% probability that the student will pass the test

8 0

3 years ago

What is the answer to the problem i need help with?

AveGali [126]

Answer:

Step-by-step explanation:

Recall the equation for a circle:

$(x-h)^2+(y-k)^2=r^2$ , where the center is (h,k) and the radius is r.

The given equation is:

$(x+5)^2+(y+7)^2=21^2$

Another way to write this is:

$(x-(-5))^2+(y-(-7))^2=21^2$

Thus, we can see that h=-5 and k=-7.

The center is at (-5, -7).

6 0

3 years ago

Find the exact circumference of a circle with diameter equal to 8 ft. 8 ft. 16 ft. 64 ft.

maria [59]

ANSWER

8π ft

EXPLANATION

The circumference of a circle is calculated using the formula C=πd.

Where d=8 is the diameter of the circle.

We substitute d=8 into the formula to obtain,

C=8π ft.

Because we are looking for the exact circumference, we leave the answer in terms of π.

6 0

3 years ago

Read 2 more answers

Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf

erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

$(\overline{x}_1-\overline{x}_2)\pm t^*\times SE$ ,

where $(\overline{x}_1-\overline{x}_2)$ = sample mean difference .

$t^*$ = critical t value (two-tailed)

SE= Standard error.

Given : $(\overline{x}_1-\overline{x}_2)=23$

$t^*=2.262$

SE= 4.2

Now, the confidence interval for mean difference will be :-

$23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)$

Hence, the required confidence interval : (13.4996, 32.5004)

8 0

2 years ago

What i want to know it how to do this

ki77a [65]

OHHHH I REMEMBER THOSE ITS SO EASY GO TO www.anglesmatter.com and type in that lesson and it shows how to do the work and gives you the answer

3 0

3 years ago