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3 years ago

Which statement correctly compares the fraction?

Mathematics

2 answers:

raketka [301]3 years ago

4 0

B. Ecause if you had a pie, and you cut it into 5ths and another pie into 4 ths, and ate 3 slices of each you would have more of 3/4.
Hope this is fine

jek_recluse [69]3 years ago

3 0

The answer is B, 3/4 is greater than 3/5

3/4=0.75
3/5=0.6

0.75 is greater than 0.6

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What is an equation of the parabola with vertex at the origin and focus (0, 0.75)?

morpeh [17]

Answer:

$x^{2} =3y$

Step-by-step explanation:

Notice that the focus is a points on the vertical axis, that means the parabolla opens vertically, and has the form

$x^{2} =4py$

Because the parameter $p$ is positive and equal to 0.75. Additionally, the vertex is at the origin, that's why the equation is this simple.

Replacing the parameter value, we have

$x^{2} =4(0.75)y\\x^{2} =3y$

Therefore, the equation of a parabolla with vertex at the origin and focus at (0, 0.75) is $x^{2} =3y$ .

8 0

3 years ago

High of the following transformations does not result in a congruent figure

LuckyWell [14K]

Any transformation involving change of scale will not result in a congruent figure. Rotations and reflections and translations maintain congruence.

7 0

3 years ago

What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c

zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

4 0

2 years ago

Select the correct answer.

yuradex [85]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The diagram shows a logo

Charra [1.4K]

Answer/Step-by-step explanation:

✔️Find EC using Cosine Rule:

EC² = DC² + DE² - 2*DC*DE*cos(D)

EC² = 27² + 14² - 2*27*14*cos(32)

EC² = 925 - 756*cos(32)

EC² = 283.875639

EC = √283.875639

EC = 16.85 cm

✔️Find the area of ∆DCE:

Area = ½*14*27*sin(32)

Area of ∆DCE = 100.15 cm²

✔️Since ∆DCE and ∆ABE are congruent, therefore,

Area of ∆ABE = 100.15 cm²

✔️Find the area of the sector:

Area of sector = 105/360*π*16.85²

Area = 260.16 cm² (nearest tenth)

✔️Therefore,

Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)

5 0

3 years ago