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katovenus [111]
3 years ago
13

The symbol ∆hf0 stands for

Chemistry
1 answer:
Nitella [24]3 years ago
6 0

Answer:

standard heat of formation for compound

Explanation:

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How much energy, in joules, is released when 17 kilograms of granite is cooled from 45 C to 21 C?
Lostsunrise [7]
Answer is: <span>D. 327,992.8 J.
</span>m(granite) = 17 kg = 17000g.
ΔT(granite) = 21°C - 45°C = -24°C (-24K).<span>
cp(granite</span>) = 0,804 J/g·°C, <span>specific heat capacity of granite.
Q = m(granite</span>) · ΔT(granite) · cp(granite).<span>
Q = 17000 g ·(-24</span>°C)<span>· 0,804 J/g·K.
Q = -327990 J.
</span>The granite lost 327990 joules of energy.<span>
Q - </span>amount of energy gained or lost.<span> 
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8 0
3 years ago
Read 2 more answers
What causes a gas to exert pressure when confined in a container
Juli2301 [7.4K]
The molecules in gas are always trying to expand
5 0
3 years ago
In an experiment, two unknown compounds (one an alcohol and the other an ether) of equal molecular mass were dissolved in water.
-BARSIC- [3]

Answer: B. It is an ether because it is unable to to form a hydrogen bond, so it is less soluble than water

Explanation: Alcohols (ROH) are more soluble in water as they can form hydrogen bonding with water whereas ethers (ROR) are less soluble as they do not form hydrogen bonds with water.

For formation of hydrogen bond, the electronegative atom (F, Oand N) must be attached to hydrogen and in ethers (ROR), there is no hydrogen directly attached to electronegative oxygen atom, thus are less soluble in water.


4 0
3 years ago
Which of the following statements is incorrect:
Valentin [98]

Answer:

the answer is c I believe

4 0
3 years ago
The amount of I₃⁻(aq) in a solution can be determined by titration with a solution containing a known concentration of S₂O₂⁻³(aq
puteri [66]

Answer: 0.22 M

Explanation:

2S_2O_3^{2-}(aq)+I_3^-\rightarrow S_4O_6^{2-}(aq)+3I^-(aq)

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{moles}{\text {Volume in L}}

moles of Na_2S_2O_3=Molarity\times {\text {Volume in L}}=0.440\times 0.025=0.011moles

Na_2S_2O_3\rightarrow 2Na^+S_2O_3^{2-}

Thus moles of S_2O_3^{2-} = 0.011

According to stoichiometry:  

2 moles of S_2O_3^{2-}(aq) require 1 mole of I_3^

Thus 0.011 moles of S_2O_3^{2-}(aq) require=\frac{1}{2}\times 0.011=5.5\times 10^{-3} moles of I_3^-

Thus Molarity of I_3^-=\frac{5.5\times 10^{-3}}{0.025L}=0.22M

Therefore, the molarity of I_3^- in the solution is 0.22 M

5 0
3 years ago
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