Answer:
E°= E°cathode- E° anode= 0.271-0.330= -0.59V
Explanation:
NB: the stoichiometry does not affect E°values,
And the more positive the E° values , the greater it's tendency to become spontaneous and hence irreversible, and the more negative the E° values the more likely to become less spontaneous and reversible, hence the above reaction is reversible
Oxygen has six valence (outer-shell) electrons so therefore gains two more electrons to form the O-2 ion Its electron configuration is: 1s2 2s2 2p6 or Ne
If this helped mark Brainliest!
srry the pic is not clear......
l cant see it.....