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kvv77 [185]
3 years ago
9

Controls are defined as ____​

Chemistry
2 answers:
vlada-n [284]3 years ago
6 0

Answer:

I think things that are kept constant during an experiment is right.

Explanation:

wariber [46]3 years ago
4 0

Answer:

The second one is the answer

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Identify how the colligative properties of a solvent change when a solute is added, forming a solution.
Sati [7]

Colligative properties are properties that depends on ratio of the number of solute to the number of solvent . Colligative properties are essentially solvent properties that are changed by the presence of solute . The solute particles displaces some solvent molecules in the liquid phase and therefore reduce the concentration of solvent. So basically colligative properties are independent of the nature of the solute.

8 0
3 years ago
3. Svante Arrhenius developed a definition of acids and bases
makvit [3.9K]
D acid and bases are the same
7 0
3 years ago
Why or how, do electrons receive a positive charge during beta decay?
scZoUnD [109]

Answer: Beta decay occurs when a nucleus is unstable because it has too many or too few neutrons relative to protons. The nucleus emits a beta particle and energy.  In beta-minus decay, a neutron breaks down to a proton and an electron, and the electron is emitted from the nucleus.

Explanation:

6 0
3 years ago
Perform the following
docker41 [41]

Answer:

8.73

Explanation:

when you are adding or subtracting numbers, the sigfig (significant figure) is based on how many numbers after the decimal. with this info, we can see that 15.67 has 2 sigfigs and 6.943 has 3 sigfigs. when you subtract normally, you would get 8.727, which has 3 sigfigs, so you would round the last 7 up to get 8.73 with 2 sigfigs!

also it is to 2 sigfigs because we know that we go by the least number of sigfigs. hope this helped!

3 0
3 years ago
Succinic acid is a substance produced by lichens. Chemical analysis indicates it is composed of 40.68% C, 5.08% H, and 54.24% O.
zimovet [89]

Answer:  

C₂H₃O₂

Explanation:  

Assume that you have 100 g of the compound.  

Then you have 40.68 g C, 5.08 g H, and 54.24 g O.  

1. Calculate the <em>moles of each element</em>.

Moles of C  = 40.68 × 1/12.01   = 3.387 mol C

Moles of H =    5.08 × 1/1.008   = 5.010 mol H

Moles of O = 54.24 × 1/16.000 = 3.390 mol O

===============

2. Calculate the <em>molar ratios</em>.  

Divide all values by the smallest number.

C:  3.387/3.387 = 1

H: 5.010/3.387 = 1.479

O: 3.390/3.387 = 1.001

===============

3. <em>Multiply each ratio by 2 </em>

C:  2 × 1       = 2

H: 2 × 1.479 = 2.958

O: 2 × 1.001 = 2.002

===============

4. Determine <em>the empirical formula</em>

Round off all numbers to the closest integer.  

C: 2

H: 3

O: 2

The empirical formula is C₂H₃O₂.  

5 0
3 years ago
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