Answer:
2.87 m
Explanation:
Given:
Mass of the ball (m) = 60 g = 0.06 kg
Height of the tube (h) = 0.70 m
Upward force by compressed air on the ball (F) = 3.0 N
Initial velocity of the ball (u) = 0 m/s (Assume)
Final velocity of the ball at the end of tube (v) = ?
Acceleration of the ball (a) = ?
Weight of the ball is equal to the product of mass and gravity. So,
Weight (W) =
Therefore, the net force acting on the ball is equal to the difference of upward force and downward force. So,
Net force = Force by air - Weight
Now, from Newton's second law, the net force is equal to the product of object's mass and acceleration. So,
Now, acceleration (a) = 40.2 m/s²
Using equation of motion, we have:
Now, let the maximum height reached be 'H'.
So, applying energy conservation from the top of pipe to the maximum height.
Decrease in kinetic energy = Increase in potential energy.
Plug in the given values and solve for 'H'. This gives,
Therefore, the ball reaches a height of 2.87 m above the top of the tube.