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Lilit [14]
3 years ago
5

What is the pressure in a 24.0-LL cylinder filled with 32.7 gg of oxygen gas at a temperature of 319 KK? Express your answer to

three significant figures with the appropriate units.
Chemistry
1 answer:
Blizzard [7]3 years ago
8 0

Answer:

The pressure in that cylinder = 1.12atm

Explanation:

We use general gas law to calculate it. General gas law is gotten by combining Boyle's law, Charles' law and Avogadro's law. Thus

P = nRT/V

Where n = number of moles

R = the gas constant

T is the Temperature, V is the volume and P is the pressure.

Given: T = 319K, V = 24L, R = 0.0821 L.atm/K.mol

The first step is to find n using

n = mass of O2/molar mass of O2

=32.7/32

=1.0219

Now, using P =nRT/V

P = 1.0219 ×0.0821×319÷24

Therefore P = 1.12atm

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7 0
3 years ago
Which one of the following substances would be the most soluble in ccl4?
mezya [45]

One of the following substances would be the most soluble in CCl₄ is C₄H₁₀.

<h3>What is CCl₄?</h3>

CCl₄ is carbon tetra chloride is an organic compound with a sweet smell and colorless liquid.

It is used in liquid for refrigerator, as a pesticide, a propellant for aresol cans and in fire extinguisher, but it is very a harmful substance that why it is banned.

Thus, the substances would be the most soluble in CCl₄ is C₄H₁₀.

Learn more about carbon tetra chloride

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7 0
3 years ago
Carbon paired electrons
Nadusha1986 [10]

Answer:

what about carbon paired electrons? what do you need to know about them?

Explanation:

4 0
3 years ago
Milk of magnesia is often taken to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 te
Igoryamba

Answer:

8.61 mL of the HCl solution

Explanation:

The reaction that takes place is:

  • 2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O

From the given mass of Mg(OH)₂, we can calculate <u>the moles of HCl that are neutralized</u>:

  • 4x10² mg = 400 mg = 0.400g
  • 0.400g Mg(OH)₂ ÷ 58.32g/1mol = 6.859*10⁻³ mol Mg(OH)₂
  • 6.859*10⁻³ mol Mg(OH)₂ * \frac{1molHCl}{1molMg(OH)_{2}} = 3.429x10⁻³ mol HCl

Finally, to calculate the volume of an HCl solution, we need both the moles and the concentration. We can <u>calculate the concentration using the pH value</u>:

  • pH = -log[H⁺]
  • 1.4 =  -log[H⁺]
  • 10^{-1.4} = [H⁺]
  • 0.0398 M = [H⁺] = [HCl]  *Because HCl is a strong acid*

Thus, the volume is:

  • 0.0398 M = 3.429x10⁻³mol HCl / Volume
  • Volume = 8.616x10⁻³ L = 8.62 mL

6 0
4 years ago
Read 2 more answers
When an excited electron in a hydrogen atom falls from ????=5 to ????=2, a photon of blue light is emitted. If an excited electr
poizon [28]

Answer:

n = 3

Explanation:

Given the formula for the transition energy of an atom with 1 electron:

E=-13.6*Z^{2}*(\frac{1}{n_{f}^{2}}-\frac{1}{n_{i}^{2}} ) eV

For the H transition n=5 to n=2:

E=-13.6*(\frac{1}{4}-\frac{1}{25} ) eV=-2.856 eV

Then we solve for nf with Z=2 (Helium)

n_{f}=\sqrt{\frac{n_{i}^{2}*Z^{2}*13.6 eV }{2.856eV*n_{i}^{2}+13.6eV*Z^{2}} }

n_{f}=\sqrt{\frac{4^{2}*2^{2}*13.6 eV }{2.856eV*4^{2}+13.6eV*2^{2}} }=3

Is near 3, actually the energy of the transitions are:

H (5⇒2) = -2.85 eV = 434 nm (Dark blue)

He (4⇒3) = -2.64 eV = 469 nm (Light blue)

I thought it was cool to see the actual colors. Included them.

4 0
3 years ago
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