Question

If your boss says you must produce 400 g of ammonia (NH3) in order to keep your job, what mass of nitrogen should you use in this reaction? N2(g) + 3 H2(g) -> 2 NH3(g).

Answer 1

Answer:

331 g

Explanation:

Step 1: Write the balanced equation

N₂(g) + 3 H₂(g) → 2 NH₃(g)

Step 2: Calculate the moles corresponding to 400 g of ammonia

The molar mass of ammonia is 17.03 g/mol.

$400g \times \frac{1mol}{17.03g} =23.5mol$

Step 3: Calculate the moles required of nitrogen

The molar ratio of N₂ to NH₃ is 1:2.

$23.5molNH_3 \times \frac{1molN_2}{2molNH_3} =11.8molN_2$

Step 4: Calculate the mass corresponding to 11.8 moles of nitrogen

The molar mass of nitrogen is 28.01 g/mol.

$11.8 mol \times \frac{28.01g}{mol} =331 g$