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timofeeve [1]
2 years ago
5

Hurry hurry hurry plz plz

Chemistry
1 answer:
Ad libitum [116K]2 years ago
7 0

Answer:

Jonathan’s claim is right.

Explanation:

Jonathan’s claim is right because photons emitted by both sources i.e. sun and the light bulb has the same wavelength which looks practically identical to each other. But some differences in the light spectrum of sun and a light bulb i. e.  light bulb has more infrared output than visible and ultraviolet while on the other hand, sun has more visible light than infrared and ultraviolet radiations so we can say that Jonathan's claim is right about the emission of light.

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Which describes a property of water that allows plants to transfer it from their roots to their leaves? Water exhibits weak adhe
mr_godi [17]

Answer:

its b

Explanation:

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2 years ago
Which of the following best describes how wireless telephones are able to receive and produce sound from one person to another?
alina1380 [7]

D.

Electromagnetic waves are received and then vibrate a speaker which produces sound waves.

Explanation:

The telephone has a receiver-transducer component that can receive electromagnetic wave - radio waves spectrum- and transform them into electric energy. This electric energy is then transformed into sound energy by a speaker. This is how we're able to listen to a phone call.

The opposite happens when we speak on the phone. The sound energy is transformed into electric energy by a microphone – the reverse of a speaker.  The transducer now changes the electric energy into electromagnetic waves that travel through space to the recipient in the phone conversation.

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3 years ago
A sample of an ionic compound that is often used as a dough conditioner is analyzed and found to contain 4.628 g of potassium, 9
Roman55 [17]

Answer:

The empirical formula of the compound is = KBrO_3

The name of the compound is potassium bromate.

Explanation:

Mass of potassium = 4.628 g

Moles of potassium = \frac{4.628 g}{39 g/mol}=0.1187 mol

Mass of bromine = 9.457 g

Moles of bromine = \frac{9.457 g}{80 g/mol}=0.1182 mol

Mass of oxygen = 5.681 g

Moles of oxygen = \frac{5.681 g}{16 g/mol}0.3551

For empirical formula of the compound, divide the least number of moles from all the moles of elements present in the compound:

Potassium :

\frac{0.1187 mol}{0.1182 mol}=1.0

Bromine;

\frac{0.1182 mol}{0.1182 mol}=1.0

Oxygen ;

\frac{0.3551 mol}{0.1182 mol}=3.0

The empirical formula of the compound is = KBrO_3

The name of the compound is potassium bromate.

5 0
3 years ago
Ascorbic acid (H2C6H6O6; H2Asc for this problem), known as vitamin C, is a diprotic acid (Ka1= 1.0x10–5 and Ka2= 5x10–12) found
Igoryamba

Answer:

The concentrations are :

[HAsc^-]=0.000702 M

[Asc^{2-}]=5.92\times 10^{-8} M

The pH of the solution is 3.15.

Explanation:

H_2Asc\rightleftharpoons HAs^-+H^+         K_{a1}=1.0\times 10^{-5}

Initial

c                0              0

Equilibrium

c-x                x          x

K_{a1}=\frac{[HAs^-][H^+]}{[H_2Asc]}

1.0\times 10^{-5}=\frac{x\times x}{(c-x)}

1.0\times 10^{-5}=\frac{x^2}{(0.050-x)}

Solving for x:

x = 0.000702 M

[HAsc^-]=0.000702 M

HAsc^-\rightleftharpoons As^{2-}+H^+        K_{a2}=5\times 10^{-12}

Initially

x                0          0

At equilibrium ;

(x - y)            y         y

K_{a2}=\frac{[As^{2-}][H^+]}{[HAsc^-]}

5\times 10^{-12}=\frac{y\times y}{(x-y)}

5\times 10^{-12}=\frac{y^2}{(x-y)}

Putting value of x = 0.000702 M

5\times 10^{-12}=\frac{y^2}{(0.000702 -y)}

y=5.92\times 10^{-8} M

[Asc^{2-}]=5.92\times 10^{-8} M

Total concentration of [H^+]=x+y=0.000702 M+5.92\times 10^{-8} M=7.0206\times 10^{-4} M

The pH of the solution :

pH=-\log[H^+]

pH=-\log[7.0206\times 10^{-4} M}=3.15

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