Under which conditions would the solubility of a gas be greatest? high pressure and high temperature high pressure and low tempe
2 answers:
Option B: high pressure and low temperature
A gas is more soluble under high pressure and low temperature conditions.
On increasing temperature of a gas, its kinetic energy increases. The increase in kinetic energy increases the motion of particles of gas this causes most of the gaseous particles to escape from the gas phase. Thus, less particles are available to dissolve in liquid and solubility decreases.
The effect of pressure on solubility of gas can be explained with the help of Henry's law. According to the law, at constant temperature, solubility of gas and partial pressure of gas are related to each other as follows:
Here, p is the partial pressure of the gas, is Henry's law constant, and
c is the concentrate of the gas.
According to above relation, concentration of gas decreases on decreasing partial pressure. Thus, on increasing pressure, concentration of gas increases this increases the solubility of gas in liquid.
Therefore, solubility of gas is greatest at high pressure and low temperature.
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Answer : The percent by mass of the solution is 7.81 %
Explanation : Given,
Mass of NaCl = 8.75 g
Mass of solution = 112.0 g
Now we have to determine the percent by mass of the solution.
Putting values in above equation, we get:
Therefore, the percent by mass of the solution is 7.81 %
Answer:
0.0714 M for the given variables
Explanation:
The question is missing some data, but one of the original questions regarding this problem provides the following data:
Mass of copper(II) acetate:
Volume of the sodium chromate solution:
Molarity of the sodium chromate solution:
Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:
Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:
Moles of the sodium chromate solution would be found by multiplying its volume by molarity:
Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.
Write the net ionic equation for this reaction:
Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:
According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:
The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate: