Phương trình hóa học: 2Mg+O2->2Mgo
The stock solution has a volume of 0.208L. When diluted, a stock solution with a concentration of 0.30 m clo2 becomes a 0.20 m stock solution with a volume of 0.050.
A three-dimensional space's occupied volume is measured. It is frequently measured numerically with SI-derived units (such the cubic metre and litre) or with other imperial units (such as the gallon, quart, cubic inch). Volume and length are related in how they are defined (cubed).
A highly concentrated stock solution, often prepared as a 10x concentrated solution, can be described as a stock solution since it can be diluted to create a working solution. In order to prepare complex solutions with numerous constituents, stock solutions can also be utilized as a component.
0.3M*v = 0.125M*0.50L
V=0.208L
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Answer:
The answer is
<h2>40.0 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 420 g
density = 10.5 g/cm³
The volume is
We have the final answer as
<h3>40.0 mL</h3>
Hope this helps you
The osmotic pressure is a colligative property which depends upon the number of molecules and not the type of molecules
The relation between osmotic pressure and concentration is
πV = nRT
where
π = Osmotic pressure [ unit atm] = ?
V = volume
n = moles
R = gas constant = 0.0821 L atm / mol K
T = temperature = 20°C = 20 + 273.15 K = 293.15 K
also
Molarity = moles / Volume
So
Molarity = n/V = 5.5 M
Putting values
π = MRT
π = 5.5 X 0.0821 X 293.15 = 132.37 atm
Osmotic pressure of given glucose solution will be 132.37 atm
Answer:
A
Explanation:
B and D have to do with plants
and C has nothing to do with cellular resporation.
