Question

If the length of side a is 12 centimeters, mZB= 36°, and mZC= 75°, what is the length of side b?

Answer 1

Answer:

b = 7.56 cm

Step-by-step explanation:

Sum of the angles in a triangle = 180

so m∠A = 180 - 75 - 36 = 69 ;

use the law of sines:

(sin A) / a = (sin B) / b = (sin C) / C.

Now plug in ∠A = 69 into formula  (sin A) / a = (sin B) / b and solve for b:

(sin 69) / 12  = (sin 36) / b

cross multiply:

b sin 69 = 12 sin 36  divide each side by sin 69

b = {12 sin 36} / sin 69

b =  (12 sin 36) / sin 69 = 7.555........

b = 7.56