Answer:
+1/3
Explanation:
The lens equation states that:
where
f is the focal length
p is the distance of the object from the lens
q is the distance of the image from the lens
For a diverging lens, the focal length is negative: 
and we also know that the object is placed a distance of twice the focal length, so 
So we can find q from the equation above
And the magnification of the image is given by
Answer:
f(2.5) = 16.5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
Explanation:
<u>Step 1: Define</u>
<em>Identify</em>
[Function] f(x) = 6x + 1.5
[Given] f(2.5) is <em>x</em> = 2.5 for function f(x)
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function f(x)]: f(2.5) = 6(2.5) + 1.5
- Multiply: f(2.5) = 15 + 1.5
- Add: f(2.5) = 16.5
The amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
<h3>WORK DONE:</h3>
The work done by a body can be calculated by multiplying the force exerted by the distance moved. That is;
Work done = force (F) × distance (m)
According to this question, Pravat exerts a force of 30N to lift a bag of groceries 0.5 m. The work done is calculated as follows:
Work done = 30N × 0.5m
Work done = 15J
Therefore, the amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
Learn more about work done at: brainly.com/question/8119756?referrer=searchResults
