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ddd [48]
4 years ago
10

One end of a 13-foot-long ladder is resting on the top of a vertical wall. The distance from the foot of the ladder to the base

of the wall is 7 feet less than the height of the wall. How high is the wall

Physics
1 answer:
Digiron [165]4 years ago
6 0

Answer:

Height of wall is 12 ft.

Explanation:

In the shown figure, AB denotes the height of the wall, BC denotes the distance between foot of the ladder and wall and AC denotes the length of the ladder.

Let h be the height of wall. By Pythagoras Theorem,

(AB)² + (BC)² = (AC)²

According to the problem, AC = 13 ft, AB = h ft and BC = (h - 7) ft:

h² + (h-7)² = (13)²

h² + h² + 49 - 14h = 169

2h² - 14h - 120 = 0

h² - 7h - 60 = 0

By mid-term splitting,

h² - 12h + 5h - 120 = 0

h(h - 12) + 5(h - 12) = 0

(h - 12) x (h + 5) = 0

h = 12 ft or h = -5 ft

Since, height of wall cannot be negative. Hence, the height of wall is 12 ft.  

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Complete question is;

Earth moves in an elliptical orbit with the sun at one of the foci. The length of half of the major axis is 149,598,000 kilometers, and the eccentricity is 0.0167. Find the minimum distance (perihelion) and the maximum distance (aphelion) of Earth from the sun

Answer:

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Maximum distance = 152,096,286.6 km

Explanation:

The formula for the eccentricity of an ellipse is given by;

e = c/a

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a is distance from the center of ellipse to a vertex.

From the question, we are given;

a = 149,598,000

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Minimum distance = a - c

Minimum distance = 149598000 - 2498286.6

Thus;

Minimum distance = 147,099,713.4 km

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Max distance = a + c

Max distance = 149598000 + 2498286.6

Maximum distance = 152,096,286.6 km

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