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kow [346]
3 years ago
8

If u have 13 tens . How can you write it in different ways

Mathematics
2 answers:
MrMuchimi3 years ago
7 0
You have 130 or you have 1 one hundred and 3 tens
denis-greek [22]3 years ago
6 0

You can write:

10 tens and 30 ones

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Two types of memberships are available for a theme park:
sergiy2304 [10]

The equation 2v-41=0 can be used to find the number of visits that would make two memberships cost the same amount.

Step-by-step explanation:

Given,

Per month charges of type 1 = $86

Per visit charge = $3

Let,

v be the number of visits.

T(v) = 3v+86    

Per month charges of type 2 = $45

Per visit charge = $5

P(v) = 5v+45

For same amount to be charged;

T(v) = P(v)

3v+86=5v+45\\86-45=5v-3v\\41=2v\\2v-41=0

The equation 2v-41=0 can be used to find the number of visits that would make two memberships cost the same amount.

8 0
3 years ago
Write the answer in numeric form?
kondor19780726 [428]

Answer:

x=11. 38 degrees; 52 degrees

Step-by-step explanation:

90+6x-14+3x+5=180

81+9x=180

9x=99

x=11

38 degrees, 52 degrees

8 0
3 years ago
John made a triangle with all three sides the same length, 1 \frac{2}{3} ft. What is the perimeter of the triangle?
UNO [17]

Answer:

5 ft

Step-by-step explanation:

If all sides are of the same length, we can multiply the value of one side by 3, because a triangle has three sides (and the perimeter is all sides added together), to find the perimeter.

1\frac{2}{3} × 3

1\frac{2}{3} can be rewritten as \frac{5}{3}, so:

\frac{5}{3} × \frac{3}{1}

= \frac{15}{3}

The numerator & denominator share a common factor of 3, so:

5 ft is the final answer/perimeter.

hope this helps!

7 0
2 years ago
A department store buys 300 shirts for a total cost of 7,200 and sells them for $30 each. Find the percent markup.
worty [1.4K]

Step-by-step explanation:

7200 ÷ 300 = 24

30 - 24 = 6

6/24 × 100/1 = 25%

3 0
3 years ago
Read 2 more answers
Attachment pic:<br> Please help
ad-work [718]
The answer is D :)

I hope this helps! Let me know if you need help with anything else! I'd be happy to help in anyway I can! :D
5 0
3 years ago
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