All categories

3 years ago

Me James has a cylindrical that measures 4 inches in diameter and are 9 inches high. What is the volume

Mathematics

2 answers:

Kipish [7]3 years ago

7 0

The formula you would use would be V=(3.14)r^2height

o-na [289]3 years ago

3 0

The vol. of a cylinder of radius r and height h is V = pi*r^2*h.

Here, V = pi(2 inches)^2 * (9 inches)= 4*pi * 9 cubic inches.

You can write this as 36pi cubic inches, or use 3.14 for pi and come out with 113.10 cubic inches.

You might be interested in

Solve for x.

IceJOKER [234]

2x - 6 = 18
2x = 18 + 6 (24)
2x = 24
x = 12

3x + 9 = 2x + 24
3x + 9 = 2x + 24 - 9 (2x + 15)
3x = 2x + 15
3x - 2x = 15
x = 15

4x = 2.4? 0.4x = 2.4? I can't tell what the question is. Let me know in the comments and I'll answer it.

5x + 4 = 24
5x = 24 - 4 (20)
5x = 20
x = 4

2x / 3 = 4
2x = 4 * 3 (12)
x = 6

3(x + 7) = 51
3x + 21 = 51
3x = 51 - 21 (30)
3x = 30
x = 10

Hope I helped :)

5 0

3 years ago

Explain how to use mental math to express 12/25 as a percent

o-na [289]

Answer:

Step-by-step explanation:

12/25 =

12 ÷ 25 =

0.48 =

0.48 × 100/100 =

0.48 × 100% =

(0.48 × 100)% =

48%;

8 0

3 years ago

Twenty thousand, two and twelve hundredths written in Numeric Form ?

coldgirl [10]

Answer:

202.12

Step-by-step explanation:

Please mark Me brainliest!

5 0

2 years ago

Read 2 more answers

What is the area of this circle?

ddd [48]

A= 3.14 • “r”squared

3 0

3 years ago

the doctor recommended that Matt increase the number of calories you consume from 2000 to 2800 by what percent did the number of

nikdorinn [45]

Answer:

40% number of calories have increased

Step-by-step explanation:

Old Value ( Calories consume before) = 2000

New Value (increase in Calories consumed) = 2800

We need to find by what percent did the number of calories increase

To find percent increase, the formula used is:

$Percent\: increase=\frac{New\:Value-Old\:Value}{Old\:Value}\times 100%$

Putting values in formula and finding percent increase

$Percent\: increase=\frac{New\:Value-Old\:Value}{Old\:Value}\times 100\%\:\\Percent\: increase=\frac{2800-2000}{2000}\times 100\%\: \\Percent\: increase=\frac{800}{2000}\times 100\%\: \\Percent\: increase=0.4\times 100\%\: \\Percent\: increase=40\%$

So, 40% number of calories have increased

8 0

3 years ago