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sweet [91]
3 years ago
10

Two objects interact with each other and with no other objects. Initially object A has a speed of 5 m/s and object B has a speed

of 10 m/s. In the course of their motion they return to their initial positions. Then A has a speed of 4 m/s and B has a speed of 7 m/s. We can conclude
Physics
1 answer:
Radda [10]3 years ago
4 0

Answer:

We can conclude that there is a decrease in kinetic energy of the particles due to their elastic collision, since kinetic energy is directly proportional to squared velocity of the particles.

Explanation:

Given:

initial velocity of particle A, Ua = 5m/s

initial velocity of particle B, Ub = 10 m/s

final velocity of particle A, Va = 4m/s

final velocity of particle B, Vb = 7m/s

For particle A:

The final velocity is 1 less than the initial velocity.

For particle B:

The final velocity is 3 less than the initial velocity.

We can conclude that there is a loss in kinetic energy due to elastic collision of the two particles, since kinetic energy is directly proportional to squared velocity of the particles. A decrease in velocity means decrease in kinetic energy.

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Answer:

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8 0
3 years ago
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N in-ground swimming pool has the dimensions shown in the drawing. It is filled with water to a uniform depth of 3.00 m. The den
Doss [256]

Answer:

The pressure is  P = 1.31*10^{5} \ Pa

Explanation:

From the question we are told that

    The depth of the swimming pool is  d =  3.00 \  m

     The density of water is  \rho = 1.00*10^{3} \  kg /m^3

Generally the  total pressure exerted on the bottom of the swimming pool is mathematically represented as

          P = P_o + \rho * g * h

Here P_o is the atmospheric pressure with value

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So

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=>     P = 130725 \ Pa

=>    P = 1.31*10^{5} \ Pa

     

7 0
3 years ago
A mass on a spring oscillates with a period T. Part A If both the mass and the force constant of the spring are doubled, the new
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Answer:

The new time period will be T.

Explanation:

The time period in terms of spring constant and mass is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

If mass and force constant is doubled, m' = 2m and k' = 2k

New time period is given by :

T'=2\pi\sqrt{\dfrac{m'}{k'}}

T'=2\pi\sqrt{\dfrac{2m}{2k}}

T'=2\pi\sqrt{\dfrac{m}{k}}

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Answer:

a. the motion is both parallel and perpendicular

Explanation:

I did grad point :)

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Give four importantnce of recycling ​
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