Answer:
For Xenon fluoride, the average bond energy is 132kj/mol
For tetraflouride,the average bond energy is 150.5kj/mol.
For hexaflouride, the average bond energy is 146.5 kj/mol
Explanation:
For xenon fluoride
105/2 = 52.5
For F-F
159/2 = 79.5
Average bond energy of Xe-F = 79.5 + 52.5 = 132kj/mole
For tetraflouride
284/4 = 71
For F-F
159/2 = 79.5
Average bond energy = 79.5 + 71 = 150.5kj/mol
For hexaflouride
402/6 = 67
F-F = 159/2 = 79.5
Average bond energy = 67 + 79.5 = 146.5kj/ mol
[r] =6
Solve for r by simplifying both sides of the equation, then isolating the variable.
<em> </em>I hope this makes sense
Answer:
1.42
Explanation:
<em> got it right on my homework </em>
A motorcycle speeding up on the highway because kinetic involve movement
Answer:
F = 100 Newtons
Explanation:
F = ?
m = 0.04kg
u = 0m/s ==> u is just an abbreviation for initial velocity, it is conventional.
s = 50m ==> s is just an abbreviation for distance, it is conventional.
v = 500m/s ==> v is just an abbreviation for final velocity, it is conventional.

Then F = ma = 0.04 x 2500 = 100N