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baherus [9]
3 years ago
10

The Fitness Log is:

Physics
1 answer:
Molodets [167]3 years ago
8 0

Answer:

D.  A record of all the physical activity you complete in one week.

Explanation:

A "Fitness Log" allows you to keep track of your workout or exercise. Therefore, it is <em><u>a record of the different workout you've managed to complete within a time frame</u></em>. It gives you several information such as the<em> type of workout you've completed, its duration and the time of the day it was performed</em>. This makes a person motivated to exercise because he can see his progress. He may also include <em>his mood before and after workout</em> in order to become more mindful in exercising and many other things.

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A cylindrical capacitor is made of two concentric cylinders. The inner cylinder has radius r1 = 4 mm, and the outer one a radius
vladimir1956 [14]

Answer:

E = 9.62*10^-8 J

Explanation:

The energy stored in a capacitor is given by the following formula:

E=\frac{1}{2}CV^2     (1)

E: energy stored

C: capacitance

V: potential difference of the capacitor = 4 V

The capacitance for a concentric cylindrical capacitor is:

C=\frac{2\pi \epsilon_o L}{ln(\frac{r_2}{r_1})}     (2)

L: length of the capacitor = 150m

r2: radius of the outer cylinder  = 8mm = 8*10^-3m

r1: radius of the inner cylinder = 4mm = 4*10^-3m

εo: dielectric permittivity of vacuum = 8.85*10^-12C^2/Nm^2

You replace the expression (2) into the equation (1) and replace the values of all parameters:

E=\frac{1}{2}(\frac{2\pi \epsilon_o L}{ln(\frac{r_2}{r_1})})V^2\\\\E=\frac{\pi \epsilon_o L}{ln(\frac{r_2}{r_1})}V^2\\\\E=\frac{\pi (8.85*10^{-12}C^2/Nm^2)(150m)}{ln(\frac{8*10^{-3}m}{4*10^{-3}m})}(4V)^2\\\\E=9.62*10^{-8}J

The energy stored in the cylindrical capacitor is 9.62*10-8 J

4 0
3 years ago
Suppose a lion running at a velocity of 10 m/s east slows
iris [78.8K]

Answer:

a=0.34\ m/s^2

Explanation:

Given that,

Initial velocity, u = 10 m/s

Final velocity, v = 0 (stops)

Time, t = 30 s

We need to find the acceleration of the lion.

We know that,

Acceleration = rate of change of velocity

a=\dfrac{v-u}{t}\\\\a=\dfrac{10-0}{30}\\\\a=0.34\ m/s^2

So, the acceleration of the lion is 0.34\ m/s^2.

5 0
3 years ago
What happens to the boiling point of water as you climb higher up a mountain?
Maksim231197 [3]
The higher the pressure, the higher boiling point of water. At lower the pressure, the boiling point of water comes down. So, the lower pressure inreases the boiling resulting more evaporation. As we go higher in altitude, the atmospheric pressure decreases. This results in decreasing the boiling point at higher altitude and increase in boiling of water. In fact, at the sea level ,the the sea water boils at 100 degree C where atmospheric pressre is normal. However , the boiling takes place at a lower temperature at the top of a mountain due to low pressure. In other words the boling is faster at the top of a mountain than that at its foot.
4 0
3 years ago
A racing car whose mass is 1.2 X 10^3 kg is travelling at 8.9 m/s. It stops with a constant deceleration in a distance of 1.8X10
Alexeev081 [22]

given that initial speed of the car is

v_i = 8.9 m/s

now after travelling the distance d = 1.8 * 10^1 m the car will stop

so here we can use kinematics to find the acceleration of car

v_f^2 - v_i^2 = 2 a d

0 - 8.9^2 = 2 a d

here we have

- 79.21 = 2*(18)*a

a = -2.2 m/s^2

net force applied due to brakes of car is given by Newton's II law

F = ma

here we have

mass = 1.2 * 10^3 kg

F_{net} = 1.2 * 10^3 * 2.2

F_{net} = 2.64 * 10^3 N

now we can say

F_{net} = F_1 + F_2

2.64 * 10^3 = 1.8 * 10^3 + F_2

F_2 = 8.4 * 10^2 N

So the force applied due to brakes is given as above

7 0
3 years ago
An airline employee tosses two suitcases in rapid succession with a horizontal velocity of 7.2 ft/s onto a 50-lb baggage carrier
zalisa [80]

Answer:

m₁ = 70 lb

Explanation:

Here we will use the law of conservation of momentum:

m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃

where,

m₁ = mass of first suitcase = ?

m₂ = mass of second suitcase = 30 lb

m₃ = mass of baggage carrier = 50 lb

u₁ = initial speed of first suitcase = 7.2 ft/s

u₂ = initial speed of second suitcase = 7.2 ft/s

u₃ = initial speed of baggage carrier = 0 ft/s

v₁ = Final speed of first suitcase = 4.8 ft/s

v₂ = Final speed of second suitcase = 4.8 ft/s

v₃ = Final speed of baggage carrier = 4.8 ft/s

because after collision all three will have same speed

Therefore,

(m₁)(7.2 ft/s) + (30 lb)(7.2 ft/s) + (50 lb)(0 ft/s) = (m₁)(4.8 ft/s) + (30 lb)(4.8 ft/s) + (50 lb)(4.8 ft/s)

(m₁)(7.2 ft/s) + (216 lb ft/s) + (0 lb ft/s) = (m₁)(4.8 ft/s) + (144 lb ft/s) + (240 lb ft/s)

(m₁)(7.2 ft/s) - (m₁)(4.8 ft/s) = 168 lb ft/s

m₁ = (168 lb ft/s)/(2.4 ft/s)

<u>m₁ = 70 lb</u>

6 0
3 years ago
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