What is the axis of symmetry of y= -(x+10)^2-9
1 answer:
Answer:
Y=×^2-9
Step-by-step explanation:
(X+0)^2-9
Use the vertex form, y=a(x-h)^2+k
a=1
h=0
k=-9
And because the parabola opens up the vertex is (0,-9)
The distance from the vertex to a focus of the parabola by using the __ 1/4a__ formula:
1/4(1)
1/4
(h,k+p)
(0,-35/4)
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