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4 years ago

What elements are solids in ordinary conditions?

Chemistry

2 answers:

irga5000 [103]4 years ago

3 0

Answer:

Hydrogen, nitrogen, oxygen, fluorine, and chlorine are gases at STP.

Explanation:

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ankoles [38]4 years ago

3 0

Answer:

drop out mate

Explanation:

school is a waste of time :D

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Commercially available solution of SPT has a density of 3.10 g/mL. Water (1.00 g/mL) can be added to the original SPT solution,

Pepsi [2]

The reciprocal of the density, ρ, of a mixture is equal to the sum of the reciprocal of the densities of the constituents multiplied by their respective proportions ( $x_i$ ) in the solution, $\displaystyle \dfrac{1}{\rho_{(mixture)}} = \sum \dfrac{x_i}{\rho _i}$

The percentage of water in the 2.75 g/mL SPT solution is $\underline{16. \bar6 \ \%}$

Reason:

Known parameter:

Density of SPT = 3.10 g/mL

Density of water = 1.00 g/mL

Required:

The percentage of water in 2.75 g/mL SPT solution

Solution:

Let x the volume of water added per 100 mL of 2.75 g/mL SPT solution, we have;

Mass of water in the solution = x mL × 1.00 g/mL = x g

Mass of commercial SPT = (100 - x) mL × 3.10 g/mL = (310 - 3.1·x) g

$Density = \dfrac{Mass}{Volume}$

The density of the 2.75 g/mL SPT solution is given as follows;

$Density \ of \ 100\ mL, \ 2.75 \ g/mL = \dfrac{(310 - 3.1\cdot x + x) \ g}{100 \ mL}$

100 mL × 2.75 g/mL =( 310 - 2.1·x) g

310 - 275 = 2.1·x

$x = \dfrac{310 - 275}{2.1} = \dfrac{50}{3} = 16.\overline 6$

Given that the reference quantity of the proportion of water in the solution is 100 mL of the 2.75 g/mL SPT solution, the percentage (per 100) of water in the overall solution is the value of x

Therefore;

The percent of the SPT solution that must consist of water to give an overall density of 2.75 g/mL is x = $\displaystyle {\underline {16.\overline 6 \ \%} }$

Learn more here: brainly.com/question/13346179

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3 years ago

What is the name for Cl₇Br₄ *

Margarita [4]

Answer: no se wey jaja que le pusiste tu ?

Explanation:

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3 years ago

Which scientist is given credit for the plum pudding model of the atom

Ivanshal [37]

Ernest Rutherford is given credit for the plum pudding model of the atom. Hope this helps;)

8 0

3 years ago

Read 2 more answers

Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem

belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound Amount

Fe₂O₃ 3.95 g

H₂ 4.77 g

Fe 4.38 g

H₂O 2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

Answer: The value of equilibrium constant for given equation is $1.0\times 10^{-4}$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

For hydrogen gas:

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M$

For water:

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M$

For the given chemical equation:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of equilibrium constant for above equation follows:

$K_{eq}=\frac{[H_2O]^3}{[H_2]^3}$

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}$

Hence, the value of equilibrium constant for given equation is $1.0\times 10^{-4}$

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4 years ago

1. Ethene, C2H4, burns in oxygen according to the equation. In an experiment, 10cm3 of ethene was burnt in 50cm3 of oxygen.

lukranit [14]

Answer:

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