Answer:
34º
Step-by-step explanation: so basically you know a complementary angle is 2 angles that make a straight line and a vertical angle crosses which means 2 angles are congruent to each other so I drew a line that bisected the angle by drawing a line that cut through the right angle and i extended a line down from the right angle so now I have a vertical angle and a complementary so from here I labeled each angle <1 <2 <3 If I know angle 3 is 56º then I know 56 plus __ equals 90º I then subtracted 56 from 90 and I got 34 and since I am trying to figure out what angle 1 is I know that angle 1 and 2 are vertical angles therefore I know they are congruent to each other so <1 = 34º
Rotation doesn't matter for this question... <em>The dilation is key... you made each side of the triangle 4 times bigger</em>
<h3>Answer:</h3>
A. False:
.... if the base is 4 times bigger and the height is 4 times bigger .... <em>the area will be </em><em>16</em><em> times bigger</em>
B. True .... you just add all sides, each is 4 times bigger
C. False ... by definition of dilation, the sides grew
D. True... Size changed, but the shape stayed the same (so, did the angles)
Answer:
Only option C shows a function
Step-by-step explanation:
The vertical line test is a visual way to determine if a curve is a graph of a function or not. A function can only have one output, y, for each unique input, x. This means that a vertical line made in the domain of the function can crosses the curve of the function only once. If it crosses the curve of the function more than once, then the curve is not a function.
In option A, a vertical line would cross two values, so it is not a function.
The curve of option B is a vertical line itself, so a vertical line would intersect an infinite amount of points; then it is not a function.
Option C is a function because a vertical line would only intersect the function's curve (which is a line) once.
The Answer to the question is { }.<span>
This is because there are no answers that are odd and divisible by 2.</span>
