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Salsk061 [2.6K]
2 years ago
10

PLEASE HELP BEFORE 7 A.M. PACIFIC TIME SEE ATTACHED.

Chemistry
2 answers:
pickupchik [31]2 years ago
7 0

Answer:

(i) 32.9 mL; (ii)  37.5 mL; (iii) 21.73 mL

Explanation:

You should always try to read a measuring instrument to a tenth of the smallest scale division.

Here, you are measuring liquids, so you take the scale reading from the bottom of the meniscus.

(i) Graduated cylinder

There are 10 divisions between 30 mL and 40 mL, so each division represents 1 mL.

The level of the liquid appears to be between 32 mL and 33 mL. It is much closer to 33 mL (perhaps right on 33 mL).

You should report the volume to the nearest 0.1 mL. I would read the volume as 32.9 mL, but 32.8 and 33.0 are also acceptable.

Note: If you think the level is right on the 33 mark, you report the volume as 33.0 mL (NOT 33 mL).

(ii) Thermometer

The reading is about half-way between 87 ° and 88 °.

I would report the temperature as 87.5 °, but 87.4 ° and 87.6 ° would also be acceptable.

(iii) Buret

There are 10 divisions between 21 mL and 22 mL, so each division represents 0.1 mL.

You should estimate to the nearest 0.01 mL.

The liquid level is about a third of the way from 21.7 mL to 21.8 mL.

I would report the volume as 21.73 mL, but 21.72 mL and 21.74 mL are also acceptable.

 

anastassius [24]2 years ago
5 0
For i: 33mL
For ii: 87-88mL
For iii:22.3mL
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A student needs to prepare 50.0 mL of a 1.20 M aqueous H2O2 solution. Calculate the volume of 4.9 M H2O2 stock solution that sho
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Answer : The volume of 4.9 M H_2O_2 stock solution used to prepare the solution is, 12.24 ml

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