This problem is providing the length in inches of a rod and it is being required to convert it to centimeters. According to the following, the answer will be 43.7 cm:
<h3>Units conversion:</h3><h3 />
In science, we use units conversion to represent measurements in different types of units depending on a specific requirement. To do so, we use conversion factors based on equivalence statements, relating the required unit with the given one.
In this case, the equivalence statement between inches and centimeters is 2.54 cm = 1 in and we can use it to get the answer as shown below:
Learn more about units conversion: brainly.com/question/13016491
Answer:
True
Explanation:
True because of the law of conservation of mass, the same same amount of atoms will be on both sides of the reaction.
Radius of Xenon = 1.3Ă—10â’8 cm
Volume = 100 ml = 0.1 L
Pressure P = 1.2 atm = 121.59 Kpa
Temperature = 281 K
R = Gas Constant = 8.31 J mol^-1 K^-1
Now find the number of atoms
PV = nRT => n = PV / RT
n = (121.59 x 0.1) / (8.31 x 281) = / 2335.11 = 0.0052
Number of atoms in a mole is same as Avogadro constant A, which is 6.02 x
10^23 particles.
n = number of atoms= 0.0052
N = number of particles
Avogadro constant A = 6.02 x 10^23
n = N/A => N = n x A = 0.0052 x 6.02 x 106^23 = 3.13 x 10^20
Volume of Xe atom which would be a sphere = (4/3) x pi x r^3
Volume = = (4/3) x 3.14 x (1.3Ă—10â’8)^3 = 9.2 x 10^-24
Volume occupied by these particles = n x Volume = 3.13 x 10^20 x 9.2 x
10^-24 = 0.00288
Fraction of volume will be = 0.00288 / 0.1 = 0.0288
Answer:
1.09 L
Explanation:
There is some info missing. I think this is the original question.
<em>Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.</em>
<em />
The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:
100 g × (1 mol/255.43 g) = 0.391 mol
0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:
0.391 mol × (1 L/0.360 mol) = 1.09 L
H2O molar mass= 18.02
Use Avogadro’s constant to convert moles into particles.
71.3x6.02x10^23=429.229
There are 429.229 molecules in 71.3 moles of H2O
