Answer:
C. 12.8 liters.
Explanation:
The Standard Temperature and Pressure (STP) of a gas are 273.15 K and 100 kilopascals. From Avogadro's Law, a mole of carbon dioxide contains
molecules. If we suppose that carbon dioxide behaves ideally, then the equation of state for ideal gas is:
(1)
(1b)
Where:
- Pressure, measured in pascals.
- Volume, measured in liters.
- Amount of molecules, no unit.
- Avogadro's number, no unit.
- Ideal gas constant, measured in pascal-liters per mole-Kelvin.
- Temperature, measured in Kelvin.
If we know that
,
,
,
and
, then the volume of carbon dioxide at STP is:
![V = \frac{r\cdot R_{u}\cdot T}{N_{A}\cdot P}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7Br%5Ccdot%20R_%7Bu%7D%5Ccdot%20T%7D%7BN_%7BA%7D%5Ccdot%20P%7D)
![V = \frac{(3.44\times 10^{23})\cdot \left(8.314\times 10^{3}\,\frac{L\cdot Pa}{mol\cdot K} \right)\cdot (273.15\,K)}{(6.022\times 10^{23})\cdot (100000\,Pa)}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B%283.44%5Ctimes%2010%5E%7B23%7D%29%5Ccdot%20%5Cleft%288.314%5Ctimes%2010%5E%7B3%7D%5C%2C%5Cfrac%7BL%5Ccdot%20Pa%7D%7Bmol%5Ccdot%20K%7D%20%5Cright%29%5Ccdot%20%28273.15%5C%2CK%29%7D%7B%286.022%5Ctimes%2010%5E%7B23%7D%29%5Ccdot%20%28100000%5C%2CPa%29%7D)
![V = 12.972\,L](https://tex.z-dn.net/?f=V%20%3D%2012.972%5C%2CL)
Therefore, the correct answer is C.
Question 1: A material that causes a wave to bounce off it is called the. Answer : Reflection
Question 2: A material that takes in a wave when the wave hits is called the. Answer: Absorber
Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.
<h3>What is volume?</h3>
Volume is the area occupied by the substance and is the ratio of the mass to the density.
At STP, 1 mole of gas occupies 22.4 L of volume
Given,
Volume of ammonia reacted = 0.720 L
The combustion reaction is shown as,
![\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O](https://tex.z-dn.net/?f=%5Crm%204NH_%7B3%7D%20%2B%205O_%7B2%7D%20%5Crightarrow%204NO%20%2B6H_%7B2%7DO)
From the stoichiometry of the reaction, it can be said that,
L of ammonia reacts with
L of oxygen gas.
So, 0.720 L of ammonia will react with:
![\dfrac{ (5 \times 22.4)}{(4 \times 22.4)} \times 0.720 = 0.9 \;\rm L](https://tex.z-dn.net/?f=%5Cdfrac%7B%20%285%20%5Ctimes%20%2022.4%29%7D%7B%284%20%5Ctimes%20%2022.4%29%7D%20%5Ctimes%200.720%20%3D%200.9%20%5C%3B%5Crm%20L)
Therefore, the volume of oxygen required is 900 mL.
Learn more about volume here:
brainly.com/question/14090111
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