Which substance produces hydroxide ions in solution?

Consider the following balanced thermochemical equation for a reaction sometimes used for H₂S production: 1/8 S₈(s) + H₂(g) → H₂

castortr0y [4]

ΔH = -15.78 KJ when 25.0 g of S₈ reacts.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

The given reaction balanced equation is:

1/8 S₈(s) + H₂(g) → H₂S(g) ΔH = -20.22kj

Now,

When 1 mol will react, then ΔH = -20.2 × 8

= -161.6 KJ

When 1 mol of S8 = 8 × 32 g

= 256 g

When 256g of S8 react ΔH = -161.6 KJ

When 1 g reacts, ΔH = $\frac{-161.6}{256}$

=- 0.63125 KJ

When 25 g reacts, ΔH = - 0.63125 × 25

= -15.78 KJ

Thus from the above conclusion we can say that ΔH = -15.78 KJ when 25.0 g of S₈ reacts.

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

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4 0

1 year ago

If the measured gas pressure in a collection flask during a gas-forming reaction was determined to be 1.44 atm? If the measured

ryzh [129]

With the information given most likely in order to find the partial pressure of the gas produced you have to subtract the total air pressure in the collection flask by the atmospheric pressure since you assume that the flask started with atmospheric pressure when it was sealed and then the gas was added as the reaction took place increasing the pressure.
1.44atm-0.95 atm=0.49atm

6 0

3 years ago

How could maglev trains help improve people's lives? Write three paragraphs. First summarize the author's criticism of conventio

skelet666 [1.2K]

Maglev trains were created to connect Shanghai Pudong International Airport to Central Pudong. Transrapid, another name for the Maglev train is said to be the fastest train. It can run up to 270/mph in just eight minutes.
Compared to other transportation systems, Transrapid is faster and more cost effective. It has less maintaining coverage and zero sounds compared to the ordinary ones.
This kind of train is one of the most effective means of transportation. It lessens traffic and pollution caused by car emission. It also saves more time for people who are always on the go.

4 0

3 years ago

Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p

UNO [17]

Answer : The equilibrium constant $K_c$ for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of $Br_2$ .

$\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}$

$\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M$

Now we have to calculate the dissociated concentration of $Br_2$ .

The balanced equilibrium reaction is,

$Br_2(g)\rightleftharpoons 2Br(aq)$

Initial conc. 1.731 M 0

At eqm. conc. (1.731-x) (2x) M

As we are given,

The percent of dissociation of $Br_2$ = $\alpha$ = 1.2 %

So, the dissociate concentration of $Br_2$ = $C\alpha=1.731M\times \frac{1.2}{100}=0.2077M$

The value of x = 0.2077 M

Now we have to calculate the concentration of $Br_2\text{ and }Br$ at equilibrium.

Concentration of $Br_2$ = 1.731 - x = 1.731 - 0.2077 = 1.5233 M

Concentration of $Br$ = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

$K_c=\frac{[Br]^2}{[Br_2]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.4154)^2}{1.5233}=0.1133$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.1133

7 0

3 years ago

The chemical equation is Mg(s) + O2(g) → MgO(s)

vredina [299]

Answer:

The magnesium will burn until consumed entirely. There is much more oxygen available in the atmosphere than needed to consume the magnesium. Thus the magnesium is the limiting reactant because it determines the amount of product formed.

Explanation:

Mg produces less amount of MgO than O2; therefore Mg is the limiting reagent. O2 produces more amount of MgO than Mg; therefore O2 is the excess reagent.

4 0

2 years ago