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Naddik [55]
3 years ago
15

Could I please have help (3m+5)-(6+5m)

Mathematics
1 answer:
9966 [12]3 years ago
5 0

Answer:

-2m -1

Step-by-step explanation:

(3m+5)-(6+5m)

Distribute the minus sign

(3m+5)-6-5m

Combine like terms

3m -5m +5 -6

-2m -1

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Let g(x, y) = cos(x + 5y). (a) Evaluate g(10, −2). g(10, −2) = (b) Find the domain of g. −1 ≤ x ≤ 1, − 1 5 ≤ y ≤ 1 5 −5 ≤ x ≤ 5,
RoseWind [281]

Answer:

since Cos(z) is a function defined for all z\in \mathbb{R}, then there is not restriction for x+5y, thus, the domain of g(x,y) is \mathbb{R}^2 and in interval notation is (-\infty,\infty)\times(-\infty,\infty)

Since Cos(x+5y)\in\mathbb{R} then the range of g(x,y) is the interval [-1,1].

4 0
4 years ago
What is the value of the arithmetic series below?
xxTIMURxx [149]

Answer:

(A)-494

Step-by-step explanation:

Given the arithmetic series

S_{19}=\sum_{k=1}^{19}4-3k

The terms in the sequence are:

  • When k=1, 4-3k=4-3(1)=1
  • When k=2, 4-3k=4-3(2)=-2
  • When k=3, 4-3k=4-3(3)=-5

Therefore, the terms in the sequence are: 1, -2, -5, ...

First term, a =1

Common difference, d=-2-1=-3

The sum of an arithmetic series, S_n=\dfrac{n}{2}[2a+(n-1)d]

Therefore:

S_{19}=\dfrac{19}{2}[2(1)+(19-1)(-3)]\\=9.5[2+18*-3]\\=9.5[2-54]\\=9.5*-52\\=-494

The correct option is A.

6 0
3 years ago
What is cot x(sin^2x+cos^2x)
shusha [124]

Answer:

cot(x)

Step-by-step explanation:

cot\theta(sin^2\theta+cos^2\theta)

cot\theta(1)

cot\theta

Recall the Pythagorean Identity sin^2x+cos^2x=1

6 0
2 years ago
Find the length of the missing side. The triangle is not drawn to scale. Show your work. (Will give brainliest)
AfilCa [17]

A^2 + b^2 = c^2

C is your hypotenuse or the longest side of the triangle; you plug in your values and solve for the missing side:

15^2 + b^2 = 17^2

225 + b^2 = 289

*-225 on both sides to get b by itself*

B^2 = 64

*to get rid of the ^2; you take the square root*

B = sqrt 64

B= 8 <— final answer

7 0
4 years ago
Read 2 more answers
Point AAA is at {(-6,-5)}(−6,−5)left parenthesis, minus, 6, comma, minus, 5, right parenthesis and point CCC is at {(4,0)}(4,0)l
Anarel [89]

Answer:

(0, 2)

Step-by-step explanation:

Given the following

coordinate A (-6, 5)

Coordinate C (4, 0)

Ratio is 2:3

Required

Coordinate of B

Using the midpoint formula expressed as;

M(X,Y) = [(ax1+bx2/a+b), ay1+by2/a+b]

x1 = -6, y1 = 5, x2 = 4 and y2 = 0

a = 2  b = 3

Get X;

X = ax1+bx2/a+b

X = 2(-6)+3(4)/2+3

X = -12+12/5

X = 0/5

X = 0

Get Y;

Y = ay1+by2/a+b

Y= 2(5)+3(0)/2+3

Y = 10/5

Y = 2

Hence the coordinate of B is at (0, 2)

5 0
3 years ago
Read 2 more answers
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