Answer:
T₂=659.25 K
Explanation:
Given that
W= 25 J
Qr = 20 J
T₁ = 20⁰ = 20 +273 = 293 K
The minimum temperature of the hot reservoir = T₂
If the engine is Carnot engine then
Qa= W+ Qr
Qa=25 + 20 J
Qa= 45 J



T₂=659.25 K
Therefore the temperature of hot reservoir will be 659.25 K
Answer:
House A requires heat at a slightest faster rate than B
Explanation:
House A requires heat at a slightest faster rate than B due to the slight high temperature the furnace A is.
The answer is A. Hope this helps. :)
Answer:
Sleep, behavior patterns, mental state, and job
Explanation: