3 years ago

7 times 9/49 Need help

1 answer:

max2010maxim [7]3 years ago

4 0

Lets change 7 to $\frac{7}{1}$

Problem becomes $\frac{7}{1} ( \frac{9}{49} )$

$\frac{7(9)}{1(49)}$

$\frac{63}{49}$ ← Since this a mixed number your answer would have to be ↓

$1 \frac{2}{7}$

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