The "unit rate" appears to be $20 per ticket.
(

)we need 3 equations
1. midpoint equation which is (

) when you have 2 points
2. distance formula which is D=

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height
so
x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(

)
midpoint=(

)
midpoint= (15,8)
point x=(15,8)
y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(

)
midpoint=(

)
midpoint=(13,4)
Y=(13,4)
legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D=

D=

D=

D=

D=

BC=

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D=

D=

D=

D=

D=

XY=

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=

and XY=

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D=

D=

D=

D=

D=

AD=

so we have
AD=

BC=
XY=

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(

) times 1/2 times

=
(

) times \sqrt{5} [/tex] =

=

=80

=252.982
X=(15,8)
Y=(13,4)
BC=

XY=

Area=80

square unit or 252.982 square units
Answer:
(14400x^4)^8
Step-by-step explanation:
sqrt10 to the 4th is 10^2 or 100, and xsqrt12 to the 4th is 144x^4. Multiply these to get (14400x^4), and take the 8th to get (14400x^4)^8.
Answer:
About 1/4 scored higher and 3/4 scored lower
Step-by-step explanation:
84 is on the right side line
Each line represents 25 % of the score
It is 75 percent ( 3 lines) of the way
She scored higher than 75% of the students and lower than 25% of the students
About 1/4 scored higher and 3/4 scored lower
Answer:
soln
A=(9,j)
x1=9,y1=j
B=(10,4)
x2=10,y2=4
slope=1
by using the fomulaof slope,
slope=y2-y1/x2-x1
1 =4-j/10-9
1 = 4-j/1
1=4-j
j=4-1
j=3