The steps below show the incomplete solution to find the value of y for the equation 4y − 2y − 4 = −1 + 13: Step 1: 4y − 2y − 4
1 answer:
You might be interested in
A semicircle is a part of a circle, and it is referred to as half of a given circle. Thud the area of the <em>semi-circle</em> window is 982 .
A circle is a shape that is <u>bounded</u> by a <em>curved</em> path which is referred to as the <em>circumference</em>. Some <u>parts</u> of a circle are radius, diameter, sector, arc, semi-circle, circumference, etc.
A <em>semicircle</em> is a <u>part</u> of a <u>circle</u>, and it is referred to as <em>half </em>of a given <em>circle</em>.
such that:
<em>Area</em> of a <u>circle</u> =
and
area of a <u>semicircle</u> =
where: r is the <u>radius </u>of the <u>circle</u>, and is a <u>constant </u>with a value of
.
Thus from the given question, it can be inferred that;
r =
= 25
r = 25 in
Thus, the area of the<em> semi-circle</em> can be determined as;
area of the <em>semi-circle</em> = *
*
= 982.1429
area of the semi-circle = 982.14
The area of the <em>semi-circle</em> window is approximately 982 .
for more clarifications on the area of a semi-circle, visit: brainly.com/question/15937849
#SPJ 1
Answer:
The following Triangles are Right Triangles:
1. Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.
2. Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.
3. Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.
Step-by-step explanation:
For a Triangle to be a Right Triangle it must Satisfy Pythagoras theorem.
i.e.
For Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.
AC² = 365² = 133225
AB² + BC² = 76² + 357² = 1333225
∴ AC² = AB² + BC²
Hence Δ ABC a Right Triangle.
For Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.
MT² = 845² = 71405
MI² + IT² = 123² + 836² = 714025
∴ MT² = MI² + IT²
Hence Δ MIT a Right Triangle.
For Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.
ML² = 101² = 10201
ME² + EL² = 20² + 99² = 10201
∴ ML² = ME² + EL²
Hence Δ MEL a Right Triangle.