Answer:
Step-by-step explanation:
Sorry
Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
SAS you have two pairs of parallel sides
you have another pair of side congruent to one another
and angle G is the same to itself.
Plug in the number from f(x) with the x value
For example
f(9)=(9)^2-25
81-25
F(9)=56
That’s one answer.
Hope it helps!
Answer:
the answer is c (x+2)^2/16 + (y+6)^2/16 <1
Step-by-step explanation:
on edge 2021 unit test got it right
