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3 years ago

For work to be accomplished we much have

Physics

2 answers:

Shkiper50 [21]3 years ago

7 0

It would help if there was answer choices, but i would think it would be Team work and determination.

posledela3 years ago

5 0

i think it would be, an action which causes movement and an opposite reaction.

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You are out running and the first mile takes you 10 minutes. The second mile takes you 20 minutes. This is an example of

scoundrel [369]

Are they any answer choices

3 0

4 years ago

A 1.0 104 kg spacecraft is traveling through space with a speed of 1200 m/s relative to Earth. A thruster fires for 2.0 min, exe

aniked [119]

We are given information:
$m=1.0* 10^{4} kg \\ v=1200m/s \\ t=2min=120s \\ F = 25kN = 25000N$

If we apply Newton's second law we can calculate acceleration:
F = m * a
a = F / m
a = 25000 / 10000
a = 2.5 m/s^2

Now we can use this information to calculate change of speed.
a = v / t
v = a * t
v = 2.5 * 120
v = 300 m/s

Force is being applied in direction that is opposite to a direction in which space craft is moving. This means that final speed will be reduced.
v = 1200 - 300
v = 900 m/s

Formula for momentum is:
p = m * v
Initial momentum:
p = 10000 * 1200
p = 12 000 000
p = 12 *10^6 kg*m/s
Final momentum:
p = 10000 * 900
p = 9 000 000
p = 9 *10^6 kg*m/s

7 0

3 years ago

You are on the steep edge of the Grand Canyon, which is miles deep. You fire an arrow at an 89-degree angle towards the canyon (

SpyIntel [72]

Answer:

a. The arrow follows a parabolic path

b. As the arrow hits the ground,

Explanation:

a Describe the arrow's trajectory, in particular noting approximately when the arrow has the most deceleration, the most acceleration, and then why the shift begins to happen. Cover all major points in the trajectory from initial shot to final resting place.

This is because, the arrow is a projectile and its path follows a parabolic curve as it goes from initial shot to final resting place.

Its equation of motion is governed by y = ut - 1/2gt² where y = parabolic path, u = initial speed of arrow, t = time and g = acceleration due to gravity.

As the arrow rises, it undergoes the most deceleration. This is because as it rises, its speed decreases until it gets to the peak of its path, where its velocity is momentarily zero.

Also, as the arrow drops, it undergoes the most acceleration. This is because as it drops from its peak, its speed increases until it gets to the bottom of its path, where its velocity is maximum and given by v = u' - gt where u' = velocity at peak = 0 m/s. So, v = 0 - gt = -gt.

b. When is the arrow moving fastest?

As the arrow hits the ground, its velocity is highest (maximum), so it is fastest at this point.

4 0

3 years ago

A plane is flying a circular path at a speed of 55.0 m/ s, with a radius of 18.3 m. The centripetal force needed to maintain thi

Nadusha1986 [10]

The plane has a centripetal acceleration a of

a = v ²/r

where v is the plane's tangential speed and r is the radius of the circle. By Newton's second law,

F = mv ²/r

Solve for the mass m :

m = Fr/v ² = (3000 N) (18.3 m) / (55.0 m/s)² ≈ 18.1 kg

7 0

3 years ago

How high off the ground is a 5.5 kg object that has a gravitational potential energy of 8500 DE=mah

umka21 [38]

Answer:

h = 157.70 meters

Explanation:

Given the following data;

Mass = 5.5 kg

Gravitational potential energy = 8500 Joules

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the height of the object;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

$G.P.E = mgh$

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the formula, we have;

8500 = 5.5*9.8*h

8500 = 53.9h

h = 8500/53.9

h = 157.70 m

7 0

3 years ago