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Delicious77 [7]
3 years ago
7

explain the main reasons why pressure and temperature play a critical role in the stability of gas hydrates. Name two situations

where methane hydrate deposits predominantly occur and discuss the key challenge(s) in locating and harvesting methane hydrate under each situation.
Physics
1 answer:
Sloan [31]3 years ago
4 0
Using the phase diagram of methane, the pressure and temperature play a critical role in its stability since a slight change in the pressure or temperature will cause a phase change. At low temperature and high pressure, methane hydrate becomes solid (methane hydrate + ice). When the temperature is increased, it becomes liquid. This is one of the main challenges in harvesting methane hydrate, its instability.  
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A ball is dropped from rest from a high window of a tall building and falls for 4 seconds. Neglecting air resistance, the final
Semenov [28]

Answer:

The final velocity of the ball is 39.2 m/s.

Explanation:

Given that,

A ball is dropped from rest from a high window of a tall building.

Time = 4 sec

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Using equation if motion

v=u+gt

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v=0+9.8\times4

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6 0
3 years ago
A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material
Llana [10]

Answer:

a) C = 40.138\,pF, b) q = 16.056\,nC, c) U = 3.212\,\mu J

Explanation:

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C = K\cdot \epsilon_{o}\cdot \frac{A}{d}

Where:

K - Dielectric constant.

\epsilon_{o} - Vaccum permitivity.

A - Plate area.

d - Distance between plates.

Hence, the capacitance of the system is:

C = (4.00)\cdot (8.854\times 10^{-12}\,\frac{F}{m} )\cdot \left(\frac{17\times 10^{-4}\,m^{2}}{0.150\times 10^{-2}\,m}\right)

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q = C\cdot V_{batt}

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q = 1.606\times 10^{-8}\,C

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U=\frac{1}{2}\cdot Q\cdot V_{batt}

U=\frac{1}{2}\cdot (1.606\times 10^{-8}\,C)\cdot (400\,V)

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U = 3.212\,\mu J

3 0
3 years ago
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Explanation:

3 0
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pogonyaev
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