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Delicious77 [7]
3 years ago
7

explain the main reasons why pressure and temperature play a critical role in the stability of gas hydrates. Name two situations

where methane hydrate deposits predominantly occur and discuss the key challenge(s) in locating and harvesting methane hydrate under each situation.
Physics
1 answer:
Sloan [31]3 years ago
4 0
Using the phase diagram of methane, the pressure and temperature play a critical role in its stability since a slight change in the pressure or temperature will cause a phase change. At low temperature and high pressure, methane hydrate becomes solid (methane hydrate + ice). When the temperature is increased, it becomes liquid. This is one of the main challenges in harvesting methane hydrate, its instability.  
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5. A construction worker on a high-rise building is on a platform suspended between two cables as illustrated below. The constru
Natalka [10]

Answer:

a) Tc = 750 [N]  ;b) See the explanation below.

Explanation:

To solve this problem, we first need a graphical explanation of this, as well as knowing the corresponding questions. Therefore, a search was carried out in google, in the attached image we will find a graphical description of the problem.

b)

The solution of this type of problem corresponds to the use of Newton's third law, applying static which tells us that the sum of the forces in a system in equilibrium without movement must be equal to zero.

a)

In this way we can find by means of a sum of forces on the y axis equal to zero:

- 850 - 450 + 550 + Tc = 0

Tc = 750 [N]

4 0
3 years ago
Assume that the function x(t) represents the length of tape that has unwound as a function of time. find θ(t), the angle through
bekas [8.4K]
We know that arc length (x(t)) is given with the following formula:
x(t)=\theta(t) r
Where r is the radius of the barrel. We must keep in mind that as barrel rolls its radius decreases because less and less tape is left on it.
If we say that the thickness of the tape is D then with every full circle our radius shrinks by d. We can write this down mathematically:
r(\theta)=r_0-\frac{D\cdot \theta}{2\pi}
When we plug this back into the first equation we get:
x(t)=\theta(r_0-\frac{D\theta}{2\pi}})\\ \frac{D\theta^2}{2\pi}-\theta r_0+x(t)=0\\
We must solve this quadratic equation.
The final solution is:
\theta=\frac{\pi r_0+\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D},\:\theta=\frac{\pi r_0-\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D}
It is rather complicated solution. If we asume that the tape has no thickness we get simply:
x(t)=\theta(r_0-\frac{D\theta}{2\pi}});D=0\\
x(t)=\theta r_0\\
\theta(t)=\frac{x(t)}{r_0}

8 0
4 years ago
A crate of 45.2-kg tools rests on a horizontal floor. You exert a gradually increasing horizontal push on it and observe that th
iragen [17]

Answer:

 μ = 0.725

Explanation:

This problem refers to Newton's second law.

       F = ma

Let's write the equations on each axis

Y Axis

      N-W = 0

     N = W

    N = mg

X axis

   F-fr = ma

With the body not started moving its acceleration is zero

  F-fr = 0

  F = fr

The friction force equation is

  fr = μ N

  fr = μ m g

Let's replace and calculate

   F = μ m g

   μ = F / mg

   μ = 321 /45.2 9.8

   μ = 0.725

8 0
4 years ago
In which phase of matter are the atoms closely packed but still able to slide past each other?
borishaifa [10]
The phase of matter is the Solid Phase.
3 0
3 years ago
You wish to move a heavy box on a rough floor. The coefficient of kinetic friction between the box and the floor is 0.9. What is
Maksim231197 [3]

Answer:

8%

Explanation:

5 0
3 years ago
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