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PSYCHO15rus [73]
2 years ago
12

6. An earthquake releases two types of traveling seismic waves, called transverse and longitudinal waves. The average speed of t

he transverse and longitudinal waves in rock are 9.1 km/s and 5.7 km/s respectively. A seismograph records the arrival of the transverse waves 71 s before that of the longitudinal waves. Assuming the waves travel in straight lines, how far away is the center of the earthquake?
Physics
1 answer:
zubka84 [21]2 years ago
6 0

Answer:

The distance away the center of the earthquake is 1083.24 km.

Explanation:

Given that,

Speed of transverse wave = 9.1\ km/s

Speed of longitudinal wave = 5.7 km/s

Time = 71 sec

We need to calculate the distance of transverse wave

Using formula of distance

d=v\times t

d=9.1\times t....(I)

The distance of longitudinal wave

d=5.7\times (t+71)....(II)

From the first equation

t=\dfrac{d}{9.1}

Put the value of t in equation (II)

d =5.7\times(\dfrac{d}{9.1}+71)

\dfrac{9.1d-5.7d}{9.1}=71\times5.7

d0.3736=404.7

d =1083.24\ km

Hence, The distance away the center of the earthquake is 1083.24 km.

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   v  =   √ { 2*(KE) ] / m } ; 

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______________________________________________________
Explanation:
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The formula is:  KE = (½) * (m) * (v²) ;
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"Kinetic energy" = (½) * (mass) * (velocity , "squared")
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KE = (½) * (m) * (v²) ;  to solve for "(v)" ; velocity, which is very similar to                                          the "speed"; 
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(KE) = (½) * (m) * (v²) ;  ↔  (½)*(m)* (v²) = (KE) ; 
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</span>______________________________________________________
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