Answer:
Explanation:
Given two mass on an incline code 
and 
and an angle of inclination 
. 
. Assume that is the weight being pulled up and the hanging weight.
-The equations of motion from Newton's Second Law are:
where a is the acceleration.
#Substituting for 
(tension) gives:
#and solving for 
which is the system's acceleration.
Radius of nuclei is given by formula
now we can say volume of the nuclei is given as
now the density is given as
density = mass / volume
mass of nuclei = mass of neutron + mass of protons
Now density is given as
here we know that
= 1.2 fm
So from above we can say that density of all nuclei is almost same.
1. A
2.B
3. True
4. False
5.B
6.B
7.B
8.True
9 true
10 true
11 true
12 C
13 D
15true
Fe=K Q1/Q2/d2
Q1 is the first charge
Q2 is the second charge
d is the distance
K= 9x10^9 NM^2/C2
Now let’s plug the numbers
Fe=9x10^9NM^2/C2 (2x10^-4C)(8x10^-4C) / (0.3m^2) you notice we took away the negative charges when we plugged the charges
Ok now we notice that we have C2 which is C to the power 2 we can write it as C^2 and we have two CSU’s beside each one of the charges we can get rid of them all by curtailment
And we can curtailment the M^2and the other M^2
Now we left with only 9x10^9N (2x10^-4)(8x10^-4)/ 0.3
Let’s multiply the (9)(2)(8)=144
And add the exponents (9)+(-4)+(-4)=1
So now we got 144x10N divide by the distance which is 0.3
144x10N / 0.3 = 4800N
Hope it helps u understand :)
