Answer:
15944.6 sec
Explanation:
d = distance of Pluto from earth = 32 AU = 32 x 1.496 x 10¹¹ m
v = speed of light = 1.08 x 10⁹ km/hr = ( 1.08 x 10⁹) (0.278) m/s
t = time taken for the communication to reach from probe to earth = ?
Using the equation
d = v t
Inserting the values given
32 x 1.496 x 10¹¹ = (( 1.08 x 10⁹) (0.278)) t
t = 15944.6 sec
t = 1.6 x 10⁴ sec
I believe L waves arrive last at a seismometer.
hope this helps!
The pilot might be correct (I think), because, if the gravity of the planet is strong, then the planet’s gravity will pull the spaceship into its orbit, so the engines don’t need to be on for the ship to get pushed toward the planet.
It would be 3.15 in meters
Answer:
The maximum energy that can be stored in the capacitor is 6.62 x 10⁻⁵ J
Explanation:
Given that,
dielectric constant k = 5.5
the area of each plate, A = 0.034 m²
separating distance, d = 2.0 mm = 2 x 10⁻³ m
magnitude of the electric field = 200 kN/C
Capacitance of the capacitor is calculated as follows;

Maximum potential difference:
V = E x d
V = 200000 x 2 x 10⁻³ = 400 V
Maximum energy that can be stored in the capacitor:
E = ¹/₂CV²
E = ¹/₂ x 8.275 x 10⁻¹⁰ x (400)²
E = 6.62 x 10⁻⁵ J
Therefore, the maximum energy that can be stored in the capacitor is 6.62 x 10⁻⁵ J