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jasenka [17]
4 years ago
8

The continuous release of nuclear energy caused when on fission reaction triggers more nuclear reactions is a _

Chemistry
1 answer:
zlopas [31]4 years ago
8 0

Answer: These are called as nuclear chain reactions.

Explanation: Nuclear Fission reactions are the reactions in which one heavier nuclei produces two lighter daughter nuclei.

Nuclear chain reactions are defined as the chemical reactions when one neutron released in a fission reaction produces another fission reactions in other nucleus. The other nucleus again releases neutrons and a chain of reactions is formed.

These reactions are generally uncontrollable.

Hence, The continuous release of nuclear energy caused when on fission reaction triggers more nuclear reactions is a nuclear chain reaction.

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Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(
Semmy [17]

The balanced half-reaction for the product that forms at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻  → I₂ + 2e- and 2H₂O  → O₂ + 4H⁺ + 4e⁻  

<h3>What is Balanced Chemical Equation ?</h3>

The equation during which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation is called balanced chemical equation.

Now write the equation for FeI₂

At cathode:

Fe⁺² + 2e⁻ → Fe(s) Eo = - 0.44 V

2H₂O + 2e⁻ → H₂ + 2OH⁻ Eo = - 0.827 V

It is easy to decrease Fe⁺² ions than the water, the product which is formed at cathode is Iron.

At anode:

2I⁻  → I₂ + 2e-    Eo = - 0.54 V

2H₂O  → O₂ + 4H⁺ + 4e⁻    Eo = -1.23 V

O₂ gas formed at anode.

Thus from the above conclusion we can say that The balanced half-reaction for the product at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻  → I₂ + 2e- and 2H₂O  → O₂ + 4H⁺ + 4e⁻.

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

#SPJ4

6 0
2 years ago
If a chemical reaction such as photosynthesis begins with 6 atoms of carbon C , how many atoms of carbon C should be in the prod
pochemuha
B. 6 atoms of carbon C
I would think this is the answer, because one can't just delete or add atoms; otherwise, the equation would be unbalanced. This also abides with the Law of Conservation of Mass.

Plus, I also came to that conclusion because if we look at the net equation of photosynthesis:
6C O_{2} + 6H_{2}O ––> C_{6}H_{12}O_{6} + 6O_{2}
The number of Carbon atoms is 6 on both the reagent's side and the product's side.
8 0
3 years ago
Read 2 more answers
True or False: If you have a covalent compound, the first element written in the formula will always be a nonmetal
Gelneren [198K]
Might be false
Hope so
So sorry if it is wrong
5 0
3 years ago
Predict the signs of !iH, !).S, and !).G of the system for the following processes at 1 atm: (a) ammonia melts at - 60°C, (b) am
Elza [17]

Answer:

Explanation:

(a) Given,

Normal melting point of ammonia is -77.7 °C

In this process , ammonia melts at - 60°C  

Now , during the process of melting , ammonia in the solid phase changes to liquid phase, and this increases the number of particles , therefore , the sign of entropy would be positive . And since , the process is an endothermic process , hence , the change in enthalphy sign will be positive .

Even , the temperature of the ammonia is more than its normal melting point .

Therefore ,  

TΔS > ΔH

Hence ,

ΔG < 0

Therefore ,  

ΔH = Positive

ΔS = Positive  

ΔG = Negative.

(b)Given,

Normal melting point of ammonia is -77.7 °C

In this process , ammonia melts at -77.7 °C

Now , during the process of melting , ammonia in the solid phase changes to liquid phase, and this increases the number of particles , therefore , the sign of entropy would be positive . And since , the process is neither endothermic process nor exothermic process, hence , the change in enthalphy sign will be neutral / zero .

Hence ,

ΔG < 0

Therefore ,  

ΔH = 0

ΔS = Positive ΔG = Negative.

(c) Given,

Normal melting point of ammonia is -77.7 °C

In this process , ammonia melts at - 100°C  

Now , during the process of melting , ammonia in the solid phase changes to liquid phase, and this increases the number of particles , therefore , the sign of entropy would be positive . And since , the process is an endothermic process , hence , the change in enthalphy sign will be positive .

Even , the temperature of the ammonia is less than its normal melting point .

Hence ,

ΔG > 0

Therefore ,  

ΔH = Positive

ΔS = Positive  

ΔG = Negative.

7 0
4 years ago
A patient cholesterol level in blood measures 149 mg/dL. What is the patients cholesterol level in grams per liter.
jonny [76]

Answer:

Cholesterol is a fat used by the body that is produced by the body and that also comes from animal-based foods. Important numbers to know are total cholesterol, HDL or good cholesterol, LDL or bad cholesterol, and triglycerides.

HOPE THIS HELPS

: U lol BRAINLIEST PLEASE

3 0
3 years ago
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