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3 years ago

Please answer right away and don’t guess

Mathematics

1 answer:

DochEvi [55]3 years ago

6 0

Answer: Third Option

$P (M\ or\ N) = 0.8$

Step-by-step explanation:

In this case, we have two non-disjoint events.

So the probability of M or N occurring is

$P (M\ or\ N) = P(M) + P(N) - P (M\ and\ N)$

We know that in this problem

$P(M) = 0.7\\\\P(N) = 0.5$

$P(M\ and\ N) = 0.4$

$P (M\ or\ N) = 0.7 + 0.5 - 0.4$

$P (M\ or\ N) = 0.8$

The answer is the third option

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Simplify please...Simplify Simplify

4vir4ik [10]

Answer:

See images.

Step-by-step explanation:

For these kinds of problems, get a common denominator. Put everything over that common denominator and add or subtract the terms in the numerator. Combine like terms. See images.

8 0

3 years ago

A fireman needs to get water to a second-floor fire. His ladder is 30 ft long and he leans it against the vertical wall so that

Art [367]

Answer:

(a) 64°

(b) Yes, the ladder will be safe the ingredients will be used.

Step-by-step explanation:

(a) Trigonometric function of Sine is the appropriate formula to use to solve this question. The formula is given as:

sin θ = Opposite/Hypotenuse

θ = Angle formed with the ground = ?

Opposite = 27 ft

Hypotenuse = 30 ft

Hence,

sin θ = 27 /30

θ = arc sin (27/30)

θ = 64.158067237°

Approximately to the nearest whole number = 64°

(b) From the above calculation, the angle the ladder makes with the ground is 64° and now we want that angle to be 70°

64° is less than 70=

64° < 70°

Hence, the ladder will be safe the way it is positioned.

8 0

3 years ago

A cube has side length of 1 meter. Determine the volume of the cube. Include all of your calculations in your final answer.

RSB [31]

Answer:

Step-by-step explanation:

Volume of Cube = a³

a is the length of one side of cube

Volume = a³ = 1³ =1x1x1 = 1

8 0

3 years ago

Need some help with indefinite integrals pleasee

goldenfox [79]

Observe that $(x^2+2x+2)'=2x+2$ .

You have that $\int \frac{2x}{x^2+2x+2}\; dx=\int \frac{2x+2-2}{x^2+2x+2}\; dx=\int \frac{2x+2}{x^2+2x+2}\; dx+\int \frac{1}{x^2+2x+2}\; dx=I_1+2I_2$ .

To compute $I_1$ you set $y=x^2+2x+2$ , so $dy=2x+2\; dx$ . Therefore, $I_1=\int \frac{1}{y}\; dy=\ln |y|=\ln |x^2+2x+2|=\ln (x^2+2x+2)$ .

For $I_2$ observe that $x^2+2x+2=(x+1)^2+1$ . Let $y=x+1$ . Then $dy=dx$ and $I_2=\int \frac{1}{y^2+1}=\arctan y=\arctan (x+1)$ .

So, $\int \frac{2x}{x^2+2x+2}=\ln (x^2+2x+2)+2\arctan (x+1)+c$ .

8 0

4 years ago

Please help

adell [148]

Square root of 3, since it's a continous decimal

6 0

3 years ago