I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
Answer:
angle PHI
Step-by-step explanation:
Using the alternate interior angle theorem, we can figure out that PHI is congruent to PKJ
Answer:
<u>y+5 =-3</u>
x-1
y+5=-3x +3
y=-3x-2
Step-by-step explanation:
We have been given the function
We have to find the value of f(3). In order to find the same, substitute x=3 in the given function.
Now, we simplify this step by step.
First of all 
. Thus, we have
Now, we can easily simplify it by PEMDAS
Therefore, the value of f(3) is 98.
Answer:
2
Step-by-step explanation:
An arithmetic progression with first term a and common difference d has the following first 6 terms:
a, a + d, a + 2d, a + 3d, a + 4d, a + 5d
We are given a = 1 and a + 5d = 11.
1 + 5d = 11
5d = 10
d = 2
Answer: The common difference is 2.
