We can use the equation of motion:
× 
Since the acceleration and velocity are both downward, we will regard the downhill direction as positive.
Solving the quadratic:
Negative time is not possible so the second value is discarded. Time taken 
seconds
<h3>
What is a time interval in physics?</h3>
A larger span of time can be broken up into several shorter, equal-length segments. These are referred to as time periods. Consider the scenario where you wished to gauge a car's speed over an hour-long trip. You could break up an hour into ten-minute segments. A time interval is the length of time between two specific points in time.
For example, "The time difference between 3:00 and 4:00 is 1 hour."
To learn more about time interval, visit:
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Answer:
The answer is "Option D"
Explanation:
Its ranges referring to the harmonic currents of its organ pipe which are open at one end and shut at another side could be noticed saying whether a strange amount of quarter-wavelengths should equal the length of its pipe. It's also the fourth wavelengths principle to have enough space and consume a minimum of 25% of our design frequency, as we're going to be taking 40 Hz.
D determined by its temperature
Frequency = (speed) / (wavelength)
Frequency = (3 x 10⁸ m/s) / (124 x 10⁻⁹ m)
Frequency = <em>2.42 x 10¹⁵ Hz</em>
Answer:
D = 30.625 m
Explanation:
given,
Speed of the climber = 1.3 m/s
time = 2.5 s
acceleration due to gravity = 9.8 m/s²
initial speed of the kit = 1.3 m/s
velocity of the kit after 2.5 s
using equation of motion
v = u + a t
v = 1.3 + 9.8 x 2.5
v = 25.8 m/s
distance travel by the kit in 2.5 s
v² = u² + 2 g h
25.8² = 1.3² + 2 x 9.8 x h
19.6 h = 663.95
h = 33.875 m
distance travel by the rock climber in 2.5 s
distance = speed of climber x time
h' = 1.3 x 2.5
h' = 3.25 m
Distance between kit and rock climber
D = h - h'
D = 33.875 - 3.25
D = 30.625 m
The kit is 30.625 m below climber.
