As per the question the total distance is given as 4 km.
We are asked to calculate the average speed.
The time taken by the body to travel each kilometre are 5.9 min,6.2 min.,6.3min. and 6 min. respectively.
The average speed of a body is defined as the ratio of total distance travelled by the body to the total time.
Mathematically the average speed is written as _
V= Total distance/Total time
i.e V = S/T
Where S is the total distance travelled and T is the total time
Here total distance (S)= 4 km
The total time T= (5.9+6.2 +6.3+ 6.0 )minutes
=24.4 min.
Hence average speed V = 4 km/24.4 min
= 0.16 km/min.
Hence the correct option is A .
Average speed of the runner is the rate at which the runner covers the total distance. Average speed of the runner in the race is given by,
Average speed = 
Where
Total distance = Distance covered by the runner from initial to final position
Total time = time taken by the runner to cover entire distance
Instantaneous speed is the speed of the runner at the particular moment in the given time. Instantaneous speed is given by,
Instantaneous speed = 
x = position of the runner at time t
t = time taken to cover distance x
Hence, Average speed and instantaneous speed are different for a runner running in the race.
Answer:
the statements the correct one is A
Explanation:
Let's analyze this exercise, vehicles have the same mass and speed, so we can use the momentum impulse ratio
I = ∫ F dt = Δp
the Δp is the same for both cars since they have the same mass and the same speeds, so the momentum is the same in both vehicles
When they indicate that vehicle A was reduced more than vehicle B, this implies that the force acted for a longer time, to have the largest reduction in size, therefore the impact force was less in car A than in car B
Resisting the statements the correct one is A
