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Westkost [7]
3 years ago
7

A student is conducting an experiment to determine how far a ball will roll down a ramp based on the angle of incline. What are

three possible controls for this experiment?
Physics
1 answer:
icang [17]3 years ago
6 0
Controls or controlled variables are variables that should remain unchanged in the experiment. These variables can have a direct effect on the dependent variable. Take note that controlled variables are NOT what is being tested but can alter results. Three possible controls for this experiment would mainly be features of the ball and the ramp.

Examples and possible answers to your question would be:

1. Mass of the ball
2. Size of the ball
3. The density of the ball
4. Type of ball
5. Length of the ramp
6. Type of ramp
7. The thickness of the ramp
<span>
Other controls that you can consider also is the environment. Wind can also affect the ball that is being rolled.</span>
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An electric current in a metal consists of moving
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the answer is 0.284 lb/in3

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A dinner plate falls vertically to the floor and breaks up into three pieces, which slide horizontally along the floor. Immediat
Olegator [25]

Answer:

Explanation:

There will be conservation of momentum along horizontal plane because no force acts along horizontal plane.

momentum of first piece = .320 kg x 2 m/s

= 0.64 kg m/s along x -axis.

momentum of second piece = .355 kg x 1.5 m/s

= 0.5325 kg m/s along y- axis .

Let the velocity of third piece be v and it is making angle of θ with x -axis .

Horizontal component of its velocity = .100 kg x v cosθ = .1 v cosθ

vertical  component of its velocity = .100 kg x v sinθ = .1 v sinθ

For making total momentum in the plane zero

.1 v cosθ = 0.64 kg m/s

.1 v sinθ = 0.5325 kg m/s

Dividing

Tanθ = .5325 / .64 = .83

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6 0
2 years ago
Read 2 more answers
A jogger runs 20 mi West and then 6.0 mi North. Find the magnitude and direction of the resultant displacement.
Black_prince [1.1K]

Answer:

The magnitude of the resultant displacement is 21 mi and its direction is 16.7° north of west

Explanation:

Hi there!

Please see the figure for a better understanding of the problem. The total displacement vector will be the sum of both displacements:

The vector for the first displacement is:

First displacement = (20 mi, 0)

The second displacement:

Second displacement = (0, 6.0 mi)

The resultant displacement will be:

R = (20 mi, 0) + (0, 6.0 mi) = (20 mi + 0, 0 + 6.0 mi) = (20 mi, 6.0 mi)

The magnitude of this vector will be:

|R| = \sqrt{(20 mi)^{2} + (6.0 mi)^{2}} = 21 mi

The magnitude of the vector displacement is 21 mi.

To find the direction of the vector R, we have to apply trigonometry:

In a right triangle the following trigonometric rule applies:

cos θ = adjacent side to the angle/ hypotenuse

In this case:

cos θ = 20 mi / magnitude of R

θ = 16.7°

The direction of the vector is 16.7° north of west.

4 0
3 years ago
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