All categories

4 years ago

900,000 divided by 3,000

Mathematics

2 answers:

mina [271]4 years ago

8 0

300.................................

TEA [102]4 years ago

8 0

900,000 divided by 3,000 is 300
900,000 / 3,000 = 300.

You might be interested in

I need help here which one is it ? Leah has 1/4-cup of oil. She pours the same amount into each of 2 oil lamps. Which equation r

Fed [463]

1/4 divided by 2 =n

5 0

3 years ago

1/3 of your birthday cake is leftover from your party. If you eat 1/4 of the leftover cake, what fraction of the original birthd

navik [9.2K]

Answer:

a twelth= 1/12

Step-by-step explanation:

3 0

3 years ago

A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. find each of the following probabili

Alja [10]

Answer: here you go

Step-by-step explanation:

1st probability: green first then blue second: 6/10*4/9 = 24/90 or about 0.27

2nd probability: blue first then green second: 4/10*6/9 = same as first answer (about 0.27)

7 0

3 years ago

(a) A parachutist lands at a point on the line between the points A and B, and the target is an operation at A. The operation fa

mr Goodwill [35]

Answer:

a) $\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}$

b) $P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736$

Step-by-step explanation:

Part a

We assume that the parachutist lands at random point in the interval (x=A,y=B) we have a continuous random variable X. And the distribution of X would be uniform $Y\sim Unif(A,B)$ . And the density function would be given by:

$f(x) =\frac{1}{B-A} , A$

And 0 for other case.

The operation fails, if parachutist's distance to A is more than five times as much as her distance to B.

So the point P in the interval (A,B) at which the distance to A is exactly 5 times the distance to B is given by:

$P= A + \frac{5}{6} (B-A)= \frac{6A +5B -5A}{6}=\frac{A+5B}{6}$

And we can find the probability desired like this:

$P(d(P,A) \geq 5 d(P,B))= P(\frac{A+5B}{6} < X< B)$

And from the cumulative distribution function of X ficen by $F(X)\frac{X-A}{B-A}$ we got:

$\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}$

Part b

For this case we assume that $X\sim Gamma (2,1)$

On this case we assume that $\alpha=2, \beta= 1$

The density function for the Gamma distribution is given by:

$P(X)= \frac{\beta^{\alpha} x^{\alpha-1} e^{-\beta x}}{\gamma(\alpha)}$

And on this case we can find the probability using the complement rule like this:

$P(X>1) = 1-P(X\leq 1)=0.736$

We can solve this problem with the following excel code:

"=1-GAMMA.DIST(1;2;1;TRUE)"

And if we do it by hand we need to do this:

$P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736$

6 0

3 years ago

The table represents the interest rates, r, at various years and the corresponding median house value, v. What does the slope of

Anvisha [2.4K]

The answer is c. v=2.4r+154. v is the dependent variable, and r is the independent variable. From the equation above, if we increase r by 1 unit, v will increase by 2.4 (154 doesn't affect because it's always a constant). The unit of r is %, while the unit of v is thousand, therefore if we increase interest rate by 1%, the median house value increases by 2.4 thousand.

5 0

3 years ago

Read 2 more answers