Answer:
The final velocity of the runner at the end of the given time is 2.7 m/s.
Explanation:
Given;
initial velocity of the runner, u = 1.1 m/s
constant acceleration, a = 0.8 m/s²
time of motion, t = 2.0 s
The velocity of the runner at the end of the given time is calculate as;
where;
v is the final velocity of the runner at the end of the given time;
v = 1.1 + (0.8)(2)
v = 2.7 m/s
Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.
Answer:
36 J
Explanation:
Let's start off with the Kinetic Energy formula: 1/2m
So to find the <em>change</em> in Kinetic Energy, you would first have to find the Kinetic Energy in the beginning and in the end.
*Note: Mass: you incorrectly wrote weight = 6 kg- because weight is a force you have to write 6 Newtons. If you are talking about the <em>mass</em>, you would write 6 kg. If you are talking about weight, you would write 6 Newtons. The difference will make significant changes to the answer, so I will give you the answer for both.
If 6 kg is the MASS:
Beginning: find the kinetic energy.
Plug in all parts of the formula: 1/2mv^2 = (6)(2 squared)=
(6)(4)= 12 J
End: find the kinetic energy.
Plug in all parts of the formula: 1/2mv^2=(6)(4 squared)=
(6)(16)= 48 J
Answer:
36 J
If 6 kg is the WEIGHT:
We know that the weight formula is mg, or mass times acceleration due to gravity (which is always 9.8 m/s^2). Plug in the numbers:
Weight = mass x acceleration due to gravity
6 = mass x 9.8
6 = 9.8m
*Divide both sides*
mass = 0.6 kg
Now, we can use the mass to find the kinetic energy.
Beginning: find the Kinetic Energy
Plug in all parts of the formula: 1/2mv^2 = (0.6)(2 squared)=
(0.6)(4)= 1.2 J
End: find the Kinetic Energy
Plug in all parts of the formula: 1/2mv^2=(0.6)(4 squared)=
(0.6)(16)= 4.8 J
Answer:
3.6 J
(this answer is not very feasible, so 36 J is the way to go. But just remember, don't mix up weight and mass again- as you can see, they lead to different answers!)
Answer:
At the focus
Explanation:
In car head lights concave mirrors are used. The light bulbs in these headlights are place along the principal axis as shown in the figure. On this Principal axis light bulbs are place at the Focus to get maximum brightness. As from the figure we can conclude that light rays coming from infinity converse at focus thus, giving maximum brightness.
