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Elis [28]
2 years ago
15

Two trolleys are moving in the same direction along a track. Trolley 1 has a momentum of 2 kg m/s and Trolley 2 has a momentum o

f 6 kg m/s. Trolley 2 catches up to Trolley 1. They collide, stick together and move off with a velocity of 2 m/s. Use the principle of conservation of momentum to work out the combined mass of the trolleys.
Physics
1 answer:
motikmotik2 years ago
8 0

Hi there!

Recall the conservation of momentum:

\large\boxed{m_1v_1 + m_2v_2 = m_1v_1' + m_2v_2'}}

For this type of inelastic collision:

\large\boxed{m_1v_1 + m_2v_2 = v_f(m_1 + m_2)}}

Thus, the initial momentum equal the final momentum if there are no external forces.

We can begin by writing out this problem:

2 + 6 = v_f(m_1 + m_2)

8 = 2(m_1 + m_2)\\\\m_1 + m_2 = \boxed{4 kg}

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The force of gravity between two objects is greatest when the objects have?
frutty [35]

The force of gravity increases as the product of their individual masses' increases

Hope it helps!

5 0
2 years ago
A 0.454-kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 21.0 N/m. The
mestny [16]

Answer:

a. Δx = 2.59 cm

Explanation:

mb = 0.454 kg , mp = 5.9 x 10 ⁻² kg , vp = 8.97 m / s , k = 21.0 N / m

Using momentum conserved

mb * (0) + mp * vp = ( mb + mp ) * vf

vf = ( mp / mp + mb) * vp

¹/₂ * ( mp + mb) * (mp / mp +mb) ² * vp ² = ¹/₂ * k * Δx²

Solve to Δx '

Δx = √ ( mp² * vp² ) / ( k * ( mp + mb )

Δx = √ ( ( 5.9 x 10⁻² kg ) ² * (8.97  m /s) ²  / [ 21.0 N / m * ( 5.9 x10 ⁻² kg + 0.454 kg ) ]

Δx = 0.02599 m  ⇒ 2.59 cm

8 0
3 years ago
A circular hole in an aluminum plate is 2.739 cm in diameter at 0.000°C. What is the change in its diameter when the temperature
prisoha [69]

Answer:

L = 2.746 cm

Explanation:

As we know that thermal expansion coefficient of aluminium is given as

\alpha = 24 \times 10^{-6} per ^oC

now we also know that after thermal expansion the final length is given as

L = L_o(1 + \alpha \Delta T)

here we know that

L_o = 2.739 cm

\alpha = 24 \times 10^{-6}

\Delta T = 108 - 0= 108^oC

now we will have

L = 2.739(1 + 24 \times 10^{-6} (108))

L = 2.746 cm

3 0
3 years ago
A fully loaded, slow-moving freight elevator has a cab with a total mass of 1200 kg, which is required to travel upward 54 m in
Lana71 [14]

Answer:

The average power is calculated as 735.0 W

Solution:

As per the question:

Total mass, M = 1200 kg

Counter mass of the elevator, m = 950

Distance traveled by the elevator, d = 54 m

Time taken, t = 3 min = 180 s

Now,

To calculate the average power:

First, we find the force needed for lifting the weight:

Force, F = (M - m)g = (1200 - 950)\times 9.8 = 2450 N

Now, the work done by this force:

W = Fd = 2450\times 54 = 132300\ J = 132.3\ kJ

Average power is given as:

P_{avg} = \frac{W}{t} = \frac{132300}{180} = 735.0\ W

4 0
3 years ago
The gravitational force is always attractive, while the electric force is both attractive and replusive. What accounts for this
tangare [24]
The gravitational force is gravity meanwhile the electric force is electric
6 0
2 years ago
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