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vazorg [7]
4 years ago
7

Why does lithostatic pressure increase more rapidly with depth than hydrostatic pressure?

Physics
1 answer:
Rudiy274 years ago
3 0
<span>Answer: Because rock is more dense than water

Lithostatic pressure is pressure caused by soil or rock. It similar to hydrostatic pressure, the pressure caused by water. Pressure is force per area and force is dependent on the mass. Rock is denser than water, thus having more mass and more force.</span>
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This was observed in 1997 what is it
Tems11 [23]
It is a comet that was a comet

5 0
4 years ago
Read 2 more answers
Jason while driving on Kukum highway at 70 m.s – 1 seeing the traffic light turn red, he applies the brake and comes to rest in
strojnjashka [21]

Answer:

35 m/s^2

Explanation:

Decceleration =   change in velocity / change in time

                        =  ( 70 m/s ) / 2 seconds = 35 m/s^2

   DEcceleration = 35 m/s^2

       Jason's speed changes by  - 35 m/s^2

6 0
2 years ago
A 1,200 kg car rolls down a hill with its brakes off and transmission in neutral. At one moment it is moving 5.0 m/s. A little l
Y_Kistochka [10]
The change in kinetic energy of the car is equivalent to the change in its potential energy. Thus:
K.E  = P.E
1/2 x mΔv² = mgΔh
h = (8.2² - 5²) / 2(9.81)
h = 2.15 meters
4 0
4 years ago
A wheel rotating with a constant angular acceleration turns through 22 revolutions during a 5 s time interval. Its angular veloc
sesenic [268]

Answer:

0.52rad/s^2

Explanation:

To find the angular acceleration you use the following formula:

\omega^2=\omega_o^2+2\alpha\theta   (1)

w: final angular velocity

wo: initial angular velocity

θ: revolutions

α: angular acceleration

you replace the values of the parameters in (1) and calculate α:

\alpha=\frac{\omega^2-\omega_o^2}{2\theta}

you use that θ=22 rev = 22(2π) = 44π

\alpha=\frac{(12rad/s)^2-(0rad/s)^2}{2(44\pi)}=0.52\frac{rad}{s^2}

hence, the angular acceñeration is 0.52rad/s^2

3 0
3 years ago
Two infinite nonconducting sheets of charge are parallel to each other, with sheet A in the x = -2.15 plane and sheet B in the x
GalinKa [24]

Answer:

a) (-367231.63i ,  367231.63i, 0) N/C

b) (0 , 0  , 367231.63i ) N/C

Explanation:

a)

Case x < -2.15

E =E_{+} + E_{+} \\E = 2*\frac{sigma}{2e_{0} } = \frac{sigma}{e_{0} }\\\\E = \frac{3.25*10^(-6)}{8.85*10^(-12) }\\\\E = - 367231.63 i

Case x > 2.15

E =E_{+} + E_{+} \\E = 2*\frac{sigma}{2e_{0} } = \frac{sigma}{e_{0} }\\\\E = \frac{3.25*10^(-6)}{8.85*10^(-12) }\\\\E = +367231.63 i

Case -2.15 < x <+2.15

E =E_{+} - E_{+} \\\\E = 0

b)

Case x < -2.15

E =E_{+} - E_{+} \\\\E = 0

Case x > 2.15

E =E_{+} - E_{+} \\\\E = 0

Case -2.15 < x <+2.15

E =E_{+} + E_{-} \\E = 2*\frac{sigma}{2e_{0} } = \frac{sigma}{e_{0} }\\\\E = \frac{3.25*10^(-6)}{8.85*10^(-12) }\\\\E = +367231.63 i

7 0
3 years ago
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