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mel-nik [20]
3 years ago
15

Structure of an AtomAtomElectronNeutronsNucleusProtonsWhat is the particle that is labeled with a question mark in the diagram?b

eta particleSave and ExitMark this and return

Physics
2 answers:
erma4kov [3.2K]3 years ago
5 0

Answer:

A quark

Explanation:

Atoms are the fundamental particle of the matter. An atom consist of a proton, a neutron and electron revolves around the nucleus. The neutrons and protons are composed of quarks. It is a type of elementary particle.

The quarks are of six types i.e. up, down, charm, strange, top and bottom. There are also antiparticles of quarks known as anti quarks.

So, a question mark in the diagram is "a quark". Hence, this is the required solution.

Law Incorporation [45]3 years ago
3 0
My answer : the particle is quark
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Kyle has a mass of 54kg and is moving at 3 m/s what is his kinetic energy
Mars2501 [29]

Answer:

243J

Explanation:

K.E = 1/2 x 54 x 3^2

K.E = 1/2 x 54 x 9

K.E = 1/2 x 486

K.E = 486/2

K.E = 243J

6 0
3 years ago
Light of wavelength 476.1 nm falls on two slits spaced 0.29 mm apart. What is the required distance from the slits to the screen
stich3 [128]

Answer:

The distance is D  =  2.6 \ m

Explanation:

From the question we are told that

    The wavelength of the light is  \lambda  =  476.1 \ nm  =  476.1 *10^{-9} \ m

      The  distance between the slit is  d =  0.29 \  mm  =  0.29 *10^{-3} \ m

       The  between the first and second dark fringes is  y =  4.2 \ mm  =  4.2 *10^{-3} \ m

Generally  fringe width is mathematically represented as

       y  =  \frac{\lambda * D }{d}

Where D is the distance of the slit to the screen

   Hence

        D  =  \frac{y *  d}{\lambda }

substituting values

       D  =  \frac{ 4.2 *10^{-3} *   0.29 *10^{-3}}{ 476.1 *10^{-9} }

        D  =  2.6 \ m

7 0
4 years ago
The 2.6-kg collar is released from rest at A and slides down the inclined fixed rod in the vertical plane. The coefficient of ki
neonofarm [45]

Answer:

The attached diagram explains the system,

Sum of Fy = 0

N=9.81

N - mgCos60 = 0

F= ukN= (0.53)(9.81) =

F= 5.12 N

So

F.d= 1/2(mv.v) - mgdsin60

-5.12*0.5 = 0.5*v^2 - 2*(9.81)*(0.5*sin60)

(a)  v = 2.436 m/s

For deflection

-F.x = 1/2(mv.v) - mgxsin60 + 1/2 (k*x*x)

by solving for with values of v, m, g, F, k

800x^2 - 11.87 x - 5.938 = 0

by solving the quadratic equation

x = 0.093, -0.079

(b) x = 0.093 m

correct Answer is 0.093m

Explanation:

3 0
3 years ago
A ball rolling down a hill was displaced 21.9 m while uniformly accelerating from rest. If the final velocity was 7.14 m/s, what
belka [17]

Answer:

a = 1.16 m/s²

Explanation:

In order to find the acceleration of the ball we will use 3rd equation of motion.

2as = Vf² - Vi²

where,

a = acceleration = ?

s = displacement = 21.9 m

Vf = Final Velocity = 7.14 m/s

Vi = Initial Velocity = 0 m/s (Since, ball starts from rest)

Therefore, using the values, we get:

2a(21.9 m) = (7.14 m/s)² - (0 m/s)²

a = (50.97 m²/s²)/(43.8 m)

<u>a = 1.16 m/s²</u>

4 0
3 years ago
two forces x and y are acting at 120 degrees to each other, if the magnitude are 8N and 10N respectively determine their resulta
Ber [7]

The resultant force of both forces is 15.62 N.

<h3 /><h3>What is resultant?</h3>

The Resultant of forces is a single force obtained when two or more forces are combined.

To calculate the resultant of the force, we use the formula below.

Formula:

  • R = √[a²+b²-2abcos∅]..................... Equation 1

Where:

  • R = Resultant of the forces.
  • ∅ = Angle between both forces

From the question,

Given:

  • a = 8 N
  • b = 10 N

Substitute these values into equation 1

  • R = √[8²+10²-2×8×10cos120°]
  • R = √[64+100-160cos120°]
  • R =√ [164-160(-0.5)]
  • R = √[164+80]
  • R = √(244)
  • R = 15.62 N

Hence, the resultant force of both forces is 15.62 N.

Learn more about resultant force here: brainly.com/question/25239010

#SPJ1

8 0
2 years ago
Read 2 more answers
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