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3 years ago

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Structure of an AtomAtomElectronNeutronsNucleusProtonsWhat is the particle that is labeled with a question mark in the diagram?b

eta particleSave and ExitMark this and return

2 answers:

erma4kov [3.2K]3 years ago

5 0

Answer:

A quark

Explanation:

Atoms are the fundamental particle of the matter. An atom consist of a proton, a neutron and electron revolves around the nucleus. The neutrons and protons are composed of quarks. It is a type of elementary particle.

The quarks are of six types i.e. up, down, charm, strange, top and bottom. There are also antiparticles of quarks known as anti quarks.

So, a question mark in the diagram is "a quark". Hence, this is the required solution.

Law Incorporation [45]3 years ago

3 0

My answer : the particle is quark

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Please help Need good grade

ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the range

Using formula of range

$R=\dfrac{v^2\sin(2\theta)}{g}$ ...(I)

The range for the other angle is

$R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}$ ....(II)

Here, distance and speed are same

On comparing both range

$\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}$

$\sin(2\theta)=\sin(2\times(\alpha-\theta))$

$\sin120=\sin2(\alpha-60)$

$120=2\alpha-120$

$\alpha=\dfrac{120+120}{2}$

$\alpha=120^{\circ}$

Hence, The other angle is 120°

6 0

3 years ago

The force of the added water produces a torque on the dam. In a simple model, if the torque due to the water were enough to caus

Fittoniya [83]

Answer:

The appropriate response is " $\tau=\frac{1}{6} PgLh^3$ ". A further explanation is described below.

Explanation:

The torque ( $\tau$ ) produced by the force on the dam will be:

⇒ $d \tau=XdF$

On applying integration both sides, we get

⇒ $\tau = \int_{0}^{a}x pgL(h-x)dx$

⇒ $= pgL\int_{0}^{h}(h-x)dx$

⇒ $=pgL[\frac{h^3}{2} -\frac{h^3}{3} ]$

⇒ $=\frac{1}{6} PgLh^3$

8 0

2 years ago

PLEASE HELP ME What does a moving charge experience when it is near a magnetic field? static friction gravity a stationary charg

attashe74 [19]

<u><em>A moving charge experiences a force as it moves close to a magnetic field present in a region.</em></u>

Explanation:

A charged particle when moves near a magnetic field is forced to move in a circular path. If there is a straight moving charged particle enters the region of the magnetic field, it's path is changed from straight path to the curved path.

The motion of the charged path inside or near the magnetic field will be a circular path and this circular path is due to the force experienced by the charged particle in the magnetic field.

The force experienced by the a charged particle as it moves near the magnetic field is termed as the Lorentz force. The expression for the Lorentz force experienced by the charged particle in the magnetic field is given by:

$\boxed{F_m=Q(\overrightarrow{v}\times\overrightarrow{B})}$

Here, $F_m$ is the magnetic force, $Q$ is the amount of charge, $\overrightarrow{v}$ is the velocity vector and $\overrightarrow{B}$ is the magnetic field intensity in the region.

Thus, <u><em>A moving charge experiences a force as it moves close to a magnetic field present in a region.</em></u>

Learn More:

1. Which one is true for the electromagnetic spectrum brainly.com/question/1619496

2. What is the current in resistor R2 brainly.com/question/3051098

3. Average current denisty of a linear wire brainly.com/question/10597501

Answer Details:

Grade: High School

Subject: Physics

Chapter: Electromagnetism

Keywords:

moving, charge, straight, circular, path, magnetic, field, amount, force, velocity, intensity, Lorentz, expression, stationary.

6 0

3 years ago

Bill and Ted are standing on a bridge 40 ft above a river. Bill drops a stone, while Ted decides to throw a stone downward at 10

USPshnik [31]

Answer:

D.

Explanation:

In order to know how long after Bill released his rock should Ted throw his if they want the stones to hit the water simultanously, we need to calculate the time needed to hit the water to both rocks independent each other, and just take the difference.

For the rock dropped by Bill, as the only influence on it is gravity (accelerating it downwards with an acceleration equal to g), and v₀ =0, we can use the following kinematic equation:

$y = \frac{1}{2} * g * t^{2}$

where y = height = 40 ft.

As all the parameters are given in SI units, it is advisable to convert this value to m, as follows:

$y = 40 ft*\frac{0.3048m}{1 ft} = 12.2 m$

Now, we can solve for t, as follows:

$t = \sqrt{\frac{2*y}{g}} = \sqrt{\frac{2*12.2m}{9.8m/s2}} = 1.58 s$

For the rock thrown down at 10 m/s, the kinematic equation we just have used becomes:

$y = v0*t +\frac{1}{2} * g * t^{2}$

This leaves us a quadratic equation on t, as follows:

$t = \frac{-10m/s}{9.8m/s2} +/- \sqrt{10m/s^{2} -4*4.9m/s2*(-12.2m)} = -1.02 s +/- 1.88s$

Taking the positive root, we have:

t = -1.02 s + 1.88 s = 0.86 s

So, in order to get that both rocks hit the water at the same time, Ted will need to wait the difference between both times:

Δt = 0.86 s - 1.58s = -0.72 s

5 0

3 years ago

The sides of a cube are each of length 1. 00 m. Each side is measured with an uncertainty

astraxan [27]

The absolute uncertainty in the volume of the cube is 0.06 m³.

We need to know about the uncertainty of measurement to solve this problem. The uncertainty of cube volume can be determined by

V = s³

|ΔV| = dV/ds x Δs

where V is volume, s is length, ΔV is uncertainty in the volume and Δs is the uncertainty of length.

From the question above, we know that

s = 1.00 m

Δs = 2% of s = 2/100 x 1 = 0.02 m

By using the uncertainty of volume formula, we get

|ΔV| = dV/ds x Δs

|ΔV| = d(s³)/ds x Δs

|ΔV| = 3s² x Δs

|ΔV| = 3. 1² x 0.02

|ΔV| = 0.06 m³

Hence, the uncertainty in the volume is 0.06 m³.

Find more on uncertainty at: brainly.com/question/1577893

#SPJ4

7 0

11 months ago