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AleksandrR [38]
3 years ago
13

A note of frequency 2000Hz has a velocity of 400 ms! What is the wavelength of the note?​

Physics
2 answers:
Rudik [331]3 years ago
8 0

Answer:

Explanation:

frequency=c/λ

c=400m/s

putting values

2000=400/λ

λ=0.2m

natka813 [3]3 years ago
8 0

f = c / λ and c = 400m/s

2000 = 400 / λ

λ = 400 / 2000

λ = 0.2 m

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The minimum height of the dive needed to achieve the given speed is v = 69 m/s is 242.9 m.

Given information:

The mass of peregrine falcon is,  m = 480

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It is given that the falcon is diving vertically downward. It can be compared with the same situation as the free-falling object under the effect of gravity only. So, the initial velocity of the falcon will be u = 0 m/s  as the motion starts with rest.

The value of the gravitational acceleration of gravity is, g = 9.80 m/s²

Now, using the third equation of motion, the minimum height  required for the final speed will be,

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h = 242.9m.

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2 years ago
A snowboarder is sliding down a hill to the right. What are the 3 forces being used?
Softa [21]

Answer:

ANswers

Explanation:

Friction, knetic, and physics

8 0
3 years ago
The moving charge in the wire causes the compass to deflect; this is because
JulijaS [17]

The answer is A. the moving charge induces a magnet field .


5 0
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A rocket with a mass of 2.0 Ã 106 kg is designed to take off from the surface of the earth by burning fuel and ejecting it with
julsineya [31]

thrust force getting from the burning of mass should balance the weight of the rocket

here thrust force is given as

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now by force balance we can say

mg = v \frac{dm}{dt}

now plug in all values in this

(2 \times 10^6)(9.8) = 3500 \times \frac{dm}{dt}

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6 0
3 years ago
Jack and Jill went up the hill to fetch a pail of water. Jack, who’s mass is 75 kg, 1.5 times heavier than Jill’s mass, fell
Travka [436]

Answer:

<em>a) Jack does more work uphill</em>

<em>b) Numerically, we can see that Jill applied the most power downhill</em>

<em></em>

Explanation:

Jack's mass = 75 kg

Jill's mass = 1.5x = 75

Jill's mass = x = \frac{75}{1.5} = 50 kg

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work = 75 x 9.81 x 15 = <em>11036.25 J</em>

similarly,

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<em>this shows that Jack does more work climbing up the hill</em>

<em></em>

b) assuming Jack's time downhill to be t,

then Jill's time = \frac{t}{3}

we recall that power is the rate in which work id done, i.e

P = \frac{work}{time}

For Jack, power = \frac{11036.25}{t}

For Jill, power =  \frac{3*7357.5}{t} =  \frac{22072.5}{t}

<em>Numerically, we can see that Jill applied the most power downhill</em>

3 0
3 years ago
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