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AleksandrR [38]
3 years ago
13

A note of frequency 2000Hz has a velocity of 400 ms! What is the wavelength of the note?​

Physics
2 answers:
Rudik [331]3 years ago
8 0

Answer:

Explanation:

frequency=c/λ

c=400m/s

putting values

2000=400/λ

λ=0.2m

natka813 [3]3 years ago
8 0

f = c / λ and c = 400m/s

2000 = 400 / λ

λ = 400 / 2000

λ = 0.2 m

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scalars

Explanation:

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3 years ago
Assume this 1.20-mm-radius copper wire is electrically neutral in the Earth reference frame, in which it is at rest and carrying
agasfer [191]

Answer:

The charge density in the system is 4.25*10^4C/m

Explanation:

To solve this problem it is necessary to keep in mind the concepts related to current and voltage through the density of electrons in a given area, considering their respective charge.

Our data given correspond to:

r=1*10^{-3}m\\v = 5.2*10^{-4}m/s\\e= 1.6*10^{-19}C

We need to asume here the number of free electrons in a copper conductor, at which is generally of 8.5 *10^{28}m^{-3}

The equation to find the current is

I = VenA

Where

I =Current

V=Velocity

A = Cross-Section Area

e= Charge for a electron

n= Number of free electrons

Then replacing,

I = (5.2*10^{-4})(1.6*10^{-19})(88.5 *10^{28})(\pi(1*10^{-3})^2)

I= 22.11a

Now to find the linear charge density, we know that

I = \frac{Q}{t} \rightarrow Q = It

Where:

I: current intensity

Q: total electric charges

t: time in which electrical charges circulate through the conductor

And also that the velocity is given in proportion with length and time,

V_d = \frac{l}{t} \rightarrow l = V_d t

The charge density is defined as

\lambda = \frac{Q}{l}\\\lambda = \frac{It}{V_d t}\\\lambda = \frac{I}{V_d}

Replacing our values

\lambda = \frac{22.11}{5.20*10{-4}}

\lambda= 4.25*10^4C/m

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5 0
3 years ago
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Answer:

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From the question,

The braking force of the lorry will be the same in magnitude as the force at which the lorry is moving.

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Where m = mass of the lorry, a = acceleration/deceleration of the lorry.

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Substitute these values into equation 1

F = 5000(8)

F = 40000 N

6 0
3 years ago
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zhannawk [14.2K]

Explanation:

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8 0
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What produced the helium now present in the sun’s atmosphere? In Jupiter’s atmosphere? In the sun’s core?
Paul [167]

Answer:

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2) the helium present in Jupiter's atmosphere came from the helium in the matter that produced our solar system.

3) the helium found in the suns core comes only from the nuclear fusion of hydrogen

7 0
3 years ago
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