The minimum height of the dive needed to achieve the given speed is v = 69 m/s is 242.9 m.
Given information:
The mass of peregrine falcon is, m = 480
The final speed reached by the peregrine falcon in a vertical dive is, v = 69 m/s
It is given that the falcon is diving vertically downward. It can be compared with the same situation as the free-falling object under the effect of gravity only. So, the initial velocity of the falcon will be u = 0 m/s as the motion starts with rest.
The value of the gravitational acceleration of gravity is, g = 9.80 m/s²
Now, using the third equation of motion, the minimum height required for the final speed will be,
v² - u² = 2gh
69² - 0² = 2 × 9.8 × h
h = 242.9m.
Therefore, the minimum height of the dive needed to achieve the given speed is 242.9 m.
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Answer:
ANswers
Explanation:
Friction, knetic, and physics
The answer is A. the moving charge induces a magnet field
.
thrust force getting from the burning of mass should balance the weight of the rocket
here thrust force is given as

now by force balance we can say

now plug in all values in this



so rate of mass burning per second will be 5600 kg per second in order to lift up the rocket
Answer:
<em>a) Jack does more work uphill</em>
<em>b) Numerically, we can see that Jill applied the most power downhill</em>
<em></em>
Explanation:
Jack's mass = 75 kg
Jill's mass = 
Jill's mass =
= 50 kg
distance up hill = 15 m
a) work done by Jack uphill = mgh
where g = acceleration due to gravity= 9.81 m/s^2
work = 75 x 9.81 x 15 = <em>11036.25 J</em>
similarly,
Jill's work uphill = 50 x 9.81 x 15 = <em>7357.5 J</em>
<em>this shows that Jack does more work climbing up the hill</em>
<em></em>
b) assuming Jack's time downhill to be t,
then Jill's time = 
we recall that power is the rate in which work id done, i.e
P = 
For Jack, power =
For Jill, power =
=
<em>Numerically, we can see that Jill applied the most power downhill</em>