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avanturin [10]
3 years ago
11

[2 Marks] What volume is occupied by 23.4 mol hydrogen at a temperature of 317 K and a pressure of 719 mm Hg?

Chemistry
1 answer:
gavmur [86]3 years ago
7 0

Explanation:

given:

n=23.4mol R=0.0821LatmK^-1mol^-1

T=317K

P=719mmhg

760mmhg=1atm

719mmhg= 719/760

=0.95atm

PV=nRT

V= nRT/P

=23.4mol*0.0821LatmK^-1mol^-1*317K/0.95atm

=578.55L

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If a stone with an original velocity of 0 is falling from a ledge and takes 8 seconds to hit the ground what is the final veloci
ziro4ka [17]
Also 0 as it hits the ground and stops
5 0
4 years ago
How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t
ddd [48]

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number  (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

                                  = 2.75 x 10²³ molecules XeF₆.

8 0
3 years ago
A volume of 500.0 mL of 0.160 M NaOH is added to 585 mL of 0.200 M weak acid ( K a = 1.28 × 10 − 5 ) . What is the pH of the res
Hitman42 [59]

Answer : The pH of the resulting buffer is, 5.22

Explanation : Given,

K_a=1.28\times 10^{-5}

First we have to calculate the moles of NaOH\text{ and }HA

\text{Moles of }NaOH=\text{Concentration of }NaOH\times \text{Volume of solution}}=0.160M\times 0.500L=0.08mol

and,

\text{Moles of }HA=\text{Concentration of }HA\times \text{Volume of solution}}=0.200M\times 0.585L=0.117mol

The balanced chemical reaction is:

HA+(aq)+OH^-(aq)\rightarrow H_2O(l)+A^-(aq)

Moles of HA left = 0.117 mol - 0.08 mol = 0.037 mol

Moles of A^- = 0.08 mol

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (1.28\times 10^{-5})

pK_a=5-\log (1.28)

pK_a=4.89

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[A^-]}{[HA]}

Now put all the given values in this expression, we get:

pH=4.89+\log (\frac{0.08}{0.037})

pH=5.22

Thus, the pH of the resulting buffer is, 5.22

5 0
4 years ago
8
GalinKa [24]

The bowl of mixed fruits is a mixture because there are several things making up the object. Hence, option (B) is correct.

What is a mixture?

  • The matter is categorized as mixtures and pure substances.
  • A mixture is defined as a combination of substances that are not chemically mixed.
  • A mixture can exist in solid, liquid, or gas form.
  • A mixture can exist in the same or in a different phase. It can be homogenous or heterogeneous.
  • If the substances are combined in the same phase, then the mixture is a homogeneous mixture.
  • But if the substances are combined in different phases, then it is a heterogeneous mixture.

Therefore, the mixed fruit bowl is a mixture, because there are several things making up the object.

Hence, option (B) is correct.

To learn more about mixture, visit: brainly.com/question/12160179

#SPJ9

8 0
2 years ago
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