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Goryan [66]
2 years ago
14

Which of the following explains why there are so many differences in the properties of peptides and proteins?

Chemistry
1 answer:
Brrunno [24]2 years ago
5 0
I think the answer is a). There are 20 kinds of amino acid can form peptides and proteins. There are many possible combinations. And there are also different folding forms and structure that can lead differences in properties.
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In the Inca civilization what was the quipo used for?
Rudik [331]

It involved knots in strings called quipu. The quipu was not a calculator, rather it was a storage device. Remember that the Incas had no written records and so the quipu played a major role in the administration of the Inca empire since it allowed numerical information to be kept.

5 0
3 years ago
How many grams of NaCl are needed to prepare 50.0 grams of a 35.0% salt solution?​
DiKsa [7]

Answer:  5.844 grams of NaCl needed to make solution.

Explanation:

3 0
3 years ago
Use Hess's Law to determine the enthalpy change (∆H) for the reaction: ClF + F2 → ClF3 Given: 2ClF + O2 → Cl2O + F2O. ∆H=167.4kJ
emmasim [6.3K]

Answer:

The enthalpy change (∆H) for the reaction is -108.7 kJ

Explanation:

Hess's law can be stated as: when the reactants are converted to products, the enthalpy change is the same, regardless of whether the reaction is carried out in one step or in a series of steps. Then, Hess's Law states that the enthalpy of one reaction can be achieved by algebraically adding the enthalpies of other reactions.

So,  to calculate the ∆H (heat of reaction) of the combustion reaction, that is, the heat that accompanies the entire reaction, you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient ( number of molecules of each compound participating in the reaction) and finally subtract them.

Enthalpy of combustion = ΔH = ∑Hproducts - ∑Hreactants

2 ClF + O₂ → Cl₂O + F₂O ∆H=167.4kJ

Cl₂O + 3 F₂O → 2 ClF₃ + 2 O₂ ∆H= -341.4kJ  

The previous equation must be inverted, and the enthalpy value is also inverted, that is, the sign is changed.

2 F₂ + O₂ →2 F₂O ∆H=-43.4kJ

Reactants and products are added or canceled, taking into account that certain substances sometimes appear as a reagent and others as a product, so they are totally eliminated (there is nothing left of them anywhere in the reaction, if the same amount in reagents and products) or partially (this substance remains, in less quantity, only on one side), obtaining:

2 ClF + 2 F₂ → 2 ClF₃

Then, as all the reactants and products have a stoichiometric coefficient of 2, dividend by that number is obtained:

ClF + F₂ → ClF₃

Adding the enthalpies algebraically, and dividing by 2, because to get the "data" reaction you had to multiply by two, you get:

ΔH= [167.4 kJ - 341.4 kJ - 43.3 kJ]÷2

ΔH= -108.7 kJ

<u><em>The enthalpy change (∆H) for the reaction is -108.7 kJ</em></u>

3 0
3 years ago
After the child exhaled all of the gas, it becomes sick
tensa zangetsu [6.8K]
What is your question about it?
5 0
2 years ago
Read 2 more answers
If you have 35 ml of gas in a closed container under 1.23 atm of pressure, what will the volume be if the pressure increased to
Over [174]

Answer:

New volume is 14.35 mL

Explanation:

When a system of a gas keeps on constant its temperature and number of moles, the pressure is modified indirectly proportional to the volume:

Pressure increased → Volume decreased

Pressure decreased → Volume increased.

The relation you have to apply is: P₁ . V₁ = P₂. V₂

1.23 atm . 35 mL = 3 atm . V₂

(1.23 atm . 35 mL / 3 atm)  = V₂

V₂ = 14.35 mL

5 0
3 years ago
Read 2 more answers
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