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Ganezh [65]
1 year ago
10

I need a chemistry questions about separating method

Chemistry
1 answer:
elixir [45]1 year ago
8 0
Distillation, crystallisation, adsorption, membrane procedures, absorption and stripping, and oxidation

Here are a few topics you could use

Question:

Different liquids boil and evaporate at different temperatures is the principle of?
Sedimentation

Fraction distillation mainly depends on?
Boiling point

A common example of fractional distillation in industries is the separation of various components of?
Crude oil


There are a few questions I would ask. Tell me if I answered this wrong cause I was a little confused

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These are three theorized causes of A) glacial melting. B) changing of the climate. C) high and low ocean tides. D) movement of
professor190 [17]

actually its D) movement of tectonic plates

8 0
3 years ago
Please help me thanks
Digiron [165]

Answer:

your finger becomes negatively charged

Explanation:

5 0
3 years ago
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Hydrofluoric acid and Water react to form fluoride anion and hydronium cation, like this HF(aq) + H_2O(l) rightarrow F(aq) + H_3
maksim [4K]

Answer:

Kc = 1.09x10⁻⁴

Explanation:

<em>HF = 1.62g</em>

<em>H₂O = 516g</em>

<em>F⁻ = 0.163g</em>

<em>H₃O⁺ = 0.110g</em>

<em />

To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:

Kc = [H₃O⁺] [F⁻] / [HF]

<em>Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:</em>

<em />

[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M

[F⁻] = 0.163g * (1mol /19.0g) = 0.00858moles / 5.6L = 1.53x10⁻³M

[HF] = 1.62g * (1mol /20g) = 0.081moles / 5.6L = 0.0145M

Kc = [1.03x10⁻³M] [1.53x10⁻³M] / [0.0145M]

<h3>Kc = 1.09x10⁻⁴</h3>
7 0
3 years ago
Can someone help pls
zysi [14]
What is the problem u need help with
3 0
2 years ago
How many moles of zinc are there in 0.890 g of zinc?
NNADVOKAT [17]

Answer:

There are  

4.517

⋅

10

23

atoms of Zn in 0.750 mols of Zn.

Explanation:

Since we know that there are  

6.022

⋅

10

23

atoms in every mole of a substance (Avogadro's Number), there are  

6.022

E

23

⋅

0.750

atoms of Zn in 0.750 mols of Zn.

4 0
2 years ago
Read 2 more answers
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