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castortr0y [4]
3 years ago
13

How many grams are in 0.535 moles of sodium bromide? (Please add work)

Chemistry
1 answer:
anastassius [24]3 years ago
3 0

Answer:

0.535 = 55.04816695 grams

Explanation:

0.009718761398284852 moles = 1 gram

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One solution has a formula C (n) H (2n) O (n) If this material weighs 288 grams, dissolves in weight 90 grams, the solution will
saw5 [17]

Explanation:

The given data is as follows.

Boiling point of water (T^{o}_{b}) = 100^{o}C = (100 + 273) K = 323 K,

Boiling point of solution (T_{b}) = 101.24^{o}C = (101.24 + 273) K = 374.24 K

Hence, change in temperature will be calculated as follows.

              \Delta T_{b} = (T_{b} - T^{o}_{b})

                           = 374.24 K - 323 K

                           = 1.24 K

As molality is defined as the moles of solute present in kg of solvent.

            Molality = \frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}

Let molar mass of the solute is x grams.

Therefore,   Molality = \frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}

                        m = \frac{288 g \times 1000}{x g \times 90}              

                          = \frac{3200}{x}

As,    \Delta T_{b} = k_{b} \times molality

                 1.24 = 0.512 ^{o}C/m \times \frac{3200}{x}

                       x = \frac{0.512 ^{o}C/m \times 3200}{1.24}

                          = 1321.29 g

This means that the molar mass of the given compound is 1321.29 g.

It is given that molecular formula is C_{n}H_{2n}O_{n}.

As, its empirical formula is CH_{2}O and mass is 30 g/mol. Hence, calculate the value of n as follows.

                n = \frac{\text{Molecular mass}}{\text{Empirical mass}}

                   = \frac{1321.29 g}{30 g/mol}

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Thus, we can conclude that the formula of given material is C_{44}H_{88}O_{44}.

4 0
3 years ago
Nonmetallic elements form ions by _____ valence electrons to complete their outer shell.
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<u>Answer:</u> Non-metals form ions when they gain electrons.

<u>Explanation:</u>

An ion is formed when an atom looses or gains electron.

  • When an atom looses electrons, it will form a positive ion known as cation.
  • When an atom gains electrons, it will form a negative ion known as anion.

Metals are the elements which have a tendency to loose electrons and thus they form cations. <u>Example:</u> Sodium will loose 1 electron to form Na^+ ion.

Non-metals are the elements which have a tendency to gain electrons and thus they form anions. <u>Example:</u> Fluorine will gain 1 electron to form F^- ion.

Hence, non-metals form ions when they gain electrons.

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